c 用递归的方法编写函数求fibonacci级数,公式为F=Fn-1 Fn-2

#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i

c:intfib(intn){return(n

把以下程序另存为fib.m%>>fib(8)Fibonacci=123456781123581321

#include#defineNUM4intdsum(intn){return(n==01:n==11:dsum(n-1)*n);}intfsum(intn){inttotal=1;for(inti=

#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

用VB写的~PrivateSubForm_Load()Dimfn&,f1&,f2&,n%f1=1:f2=1n=Val(InputBox("请输入n"))fn=f1+f2Printf1Printf2Pr

#includeintfib(intn){if(n==1||n==2)return1;elseif(n>2)returnfib(n-2)+fib(n-1);elsereturn0;}intmain()

说个递归的方法吧;intf(intn){//递归出口；//递归替;}递归出口一般为1或0：如：if(n==1||n==0)return1;//递归出口;elsef(n-1);//递归体希望采纳

#include"stdio.h"voidmain(){intn;inta,b,c;scanf("%d",&n);a=0;b=1;if(n==1)printf("0\n");elseif(

intfib(n){if(n

代码如下:OptionExplicitPrivateSubCommand1_Click()MsgBoxP(2,2)EndSubFunctionP(ByValnAsInteger,ByValxAsDou

#includeusingnamespacestd;intexc(inta,intb)//这个时候参数不分大小{if(a>b)//确保第二个数是大数{intc;c=a;a=b;b=

/>#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;c

#include <stdio.h>char* dg(char* instr, char* outstr, char* 

#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\

#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-

1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n

不想吐槽百度的排版.再问：大神，你在不在，我想拜你为师。再答：我是不是大神，真的。。。再问：你这个是C++吗，我还没学过呢我现在正在学C再答：上一个回答多了个是字你竟然没发现，打多了。。然后，我水平一

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i