C 从屏幕输入N*N的整数矩阵
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#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次
你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs
#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i
#include#includeintmain(){intm,n,i,j,s;intarr[30][30];while(scanf("%d%d",&m,&n)!=EOF){for(i=0
main(){intn,i,j;printf("\nentern:");scanf("%d",&n);for(i=0;i再问:#includevoidtrangle(intn){inti,j;for(
在你的第二个for循环中a
#includevoidperm(int*data,intn,intcurr){if(curr==n-1){for(inti=0;iprintf("%d",data[i]);printf("\n");
只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");
#includevoidtrangle(intn){inti,j,k,count=1;for(i=0;i=0;k--){printf("");}for(j=0;j
#includeintmain(){inti,n,sum;printf("请输入整数n:\n");scanf("%d",&n);for(i=1,sum=n;i{printf("%d的%d次方等于%d\
VC6.0调试通过了,while循环结构#include"stdio.h"voidmain(){inti,sum=0,n;i=1;printf("Inputn:");scanf("%d",&n);wh
#include"stdio.h"intmain(){intcnt;inti,j,max,n;ints[100];intbuf[100];printf("pleaseenternumber\n");s
#include <stdio.h>int main(){\x09int i,N;\x09scanf("%d",&N);\x09i
#include<stdio.h>int main(){ int n,i,j,k=1;
clears=0input"请输入n的值:"tonfori=1tons=s+iendfor?s
方法很多,以下是按照各边的次序填充再输出:#include<stdio.h>intmain(){inti,j,a[100][100],n,k=1;printf("pleaseinputan
#include#defineSIZE100main()\x05{\x05\x05\x05\x05intm,n,i,j,a[SIZE][SIZE];\x05\x05\x05\x05printf("请输
测试通过了都顺时针#include"stdio.h"#include"conio.h"main(){inta[50][50],b[50][50],i,j,m,n;printf("\ninputrow:
inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=
#include usingnamespacestd; intmain(){ //该程序虽然能通过评测系统的检测,但时间复杂度为O(n^3),因而有待改进 intN;//矩阵阶数 in