把下列各式因式分解 8m²n 2mn
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9(m+2n)²-16(m-n)²=(3m+6n+4m-4n)(3m+6n-4m+4n)=(7m+2n)(10n-m)
12.1)78²-22²=(78+22)*(78-22)=100*56=56002)1000²/(252²-248²)=1000²/【(25
1.原式=[2(x+y)+(x-y)][2(x+y)-(x-y)]=(3x-y)(x+3y)2.原式=9a^2b^4-6ab^2+1=(3ab^2-1)^23.原式=[(m/3)^2+n]^24.原式
(1)4a2 y2 -16a2 x2 =4a2(y2-4x2)=4a2(y+2x)(y-2x);(2)2a2 x-2ax+12x=2x(a2-a+14
1:9(m+n)²-4(2m-n)²=[3(m+n)+2(2m-n)]*[3(m+n)-2(2m-n)]=(7m+n)*(5n-m)2:25(x-y)²-(x+y)&su
(4a²+3b²)²
9a²-4(b+c)²=(3a+2b+2c)(3a-2b-2c)
/>3x³+6x⁴=x³(1+2x)6p(p+q)-4q(p+q)=(6p-4q)(p+q)=2(3p-2q)(p+q)
4xy²-4x²y-y³=-y(4x-4xy+y²)=-y(2x+y)²
解题思路:解答此题的关键是要掌握分析题中的各种信息条件,寻找题中的数量关系解题过程:解:
(1).1.(x+18)^2=(22+18)^2=16002.(2a-b)^2=(2*1/2-5/4)^2=1/16(2).(2x-3)^2=0x=3/2(3).xy(a-b)^2=5*6^2=180
25(m+n)的平方-36(m-n)的平方=[5(m+n)]²-[6(m-n)]²=(5m+5n+6m-6n)(5m+5n-6m+6n)=(11m-n)(11n-m)
(2m+3n)(2m-n)-4n(2m-n)=(2m-n)(2m+3n-4n)=(2m-n)(2m-n)=(2m-n)^2(x+y)^2(x-y)+(x+y)(y-x)^2=(x+y)(x-y)(x+
(1)4x²-20xy+25y²=(2x)²-2*2x*5y+(5y)²=(2x-5y)²(2)9-12(x-y)+4(x-y)²=3
1、9a²-4b²=(3a)²-(2b)²=(3a+2b)(3a-2b)2、4x²-25y²=(2x)²-(5y)²=(
解题思路:因式分解解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph
⒈-16分之1m³+m.=-1/16m(m²-16)=-1/16m(m+4)(m-4)⒉x⁴-16.=(x²+4)(x²-4)=(x²+4
(1)(a²+1)(a+1)(a-1)(2)(3x-2)(3x-4)(3)(x+2)(x-2)(1-2x)(4)x(2y-3z)²(z+y)(z-y)
一解:(1)原式=(x-1)(7x-7+4)=(x-1)(7x-3)(2)原式=(a-b)(x-y)(3)原式=(p-3)(6m-4n)(4)原式=(y+2)(1-20y-40)=(y+2)(-20y
1.(m+n)^4-2(m+n)²+1=[(m+n)²-1]²=[(m+n+1)(m+n-1)]²=(m+n+1)²(m+n-1)²2.a的