a=log3(2),b=log3(4)
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应该有个a≠b吧,ab=1logab=lnb/lnalogba=lna/lnb因为logab=logba所以lnb/lna=lna/lnb(lnb)^2=(lna)^2lnb=lna或者lnb=-ln
不知你的连锁公式是指什么此处可以用换底公式log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log5(7)*6log7(2)=12*log2(3)*
log243÷log9=log3^5÷log3^2=5log3÷(2log3)=5/2=2.5
=log3(5)原式=1/2*log3(30)=1/2*log3(2*3*5)=1/2*[log3(2)+log3(3)+log3(5)]=(a+b+1)/2
loga-logb=3log(c/2)loga/b=log(c/2)^3a/b=(c/2)^3a=b(c/2)^3=bc^3/8
/>因为:log32=a,log35=b,所以:log340=log38+log35=3log32+log35=3a+b因为:lg2=a,所以:lg5=lg(10/2)=lg10-lg2=1-alg8
A=2根号3/3A属于(2/3,1)B=log(3)*(log(3)*4)/log(4)*(log(3)*4)=2.8864663987286C=log2(sin72°)因为sin72°小于1所以lo
点击图片就可以看清楚了,加油!
log3八次方-2log3六次方=4log3²-2×3log3²=-2log3²=-2a
log(a)(b)*log(b)(a)=1
因为3^b=5所以b=log(3)5所以log3(根号30)=1/2log3(30)=1/2log3(2*5*3)=1/2[log(3)2+log(3)5+log3(3)]=1/2(a+b+1)
因为log(8)a+log(4)b^2=5所以1/3log(2)a+log(2)b=5①因为log(8)b+log(4)a^2=7所以1/3log(2)b+log(2)a=7②由①②将log(2)a与
log3(2)=A3^B=5log3(5)=Blog3(根号30)=log3[30^(1/2)]=1/2*log3(30)=1/2*log3(3*10)=1/2*[log3(3)+log3(10)]=
很高兴您解答.图片可能不是很清晰.
∵集合A={x|log3(x2-3x+3)=0}={1,2},B={x|mx-2=0}={2m},A∩B=B,∴B=∅,或B={1},或B={2}.当B=∅时,2m不存在,∴m
对,一样正确再问:好快的回答。。那log(a)(X)=clog(b)(X)=d用c、d表示log(ab)(X)怎么做呢。。
2log(b)x=log(a)x+log(c)x2lgx/lgb=lgx/lga+lgx/lgc把lgx约分2/lgb=1/lga+1/lgc=(lga+lgc)/(lgalgc)=lg(ac)/(l
用换底公式,左边=logab*logbc=(lgb/lga)*(lgc/lgb)=lgc/lga=logac右边=logbb*logac=1*logac=logac左边=右边所以,logab*logb