a b=3,a-b=-1 3,求a的平方-b的平方-搜答案-智慧作业帮

（3a-4b-ab)-(a-2b+3ab)=3a-4b-ab-a+2b-3ab=2a-2b-4ab=2（a-b）-4ab=2×（-1）-4×（-2）（将a-b=-1,ab=-2代入）=-2+8=6

(2a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)=2a+3b-2ab-a-4b-ab-3ab-2b+2a=3a-3b-6ab=3(a-b)-6ab已知a-b=3,ab=-33(a-b

原式=5a²b(a-b)-3ab(a-b)²-5ab²(a-b)=ab(a-b)[5a-3(a-b)-5b]=ab(a-b)(5a-3a+3b-5b)=ab(a-b)(2

(a-b)*(3a+2b)=0b/a=-3/2a/b-b/a-(a*a+b*b)/ab=-2b/a=3

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a-b=5ab=-6(a-b)^2=25a^2-2ab+b^2=25a^2-2*(-6)+b^2=25a^2+b^2=13(a+b)^2=a^2+b^2+2ab=13+2*(-6)=1(a+b)=±1

1.(A-B)+A*A+B*B+AB=(A-B)+A*A-2AB+B*B+3AB=(A-B)+（A-B）（A-B）+3AB=3-根号22.（X-1/X）的平方=X的平方-2+（1/X）的平方=X的平方

a-b=3ab2a-2b-ab/a-b+2ab=6ab-ab/3ab+2ab=5ab/5ab=1

由条件去分母得a^2+b^2=3ab,代入合并约分得2

(-a-4b-ab)-(2ab-2a-3b)-(3ab+2b-2a)=-a-4b-ab-2ab+2a+3b-3ab-2b+2a=3a-3b-6ab=3(a-b)-6ab=9+18=27

(5a-5b-ab)-(4a-6b-3ab)=5a-5b-ab-4a+6b+3ab=a+b+2ab=3-2x2=-1

由1-2(a+ab)+(ab-2b)=3A1-2a-2ab+ab-2b=3A1-2(a+b)-ab=3A1-2A-(A+2008)=3A1-2A-A-2008=3A6A=-2007A=-334.5a+

2a+2b-ab分之a+b+2ab=2(a+b)-ab分之a+b+2ab=6ab-ab分之3ab+2ab=5ab分之5ab=1

由a(a-1)-(a×a-b)=-5得a^2-a-a^2+b=-5,即a-b=5,(a-b)^2=25.(a×a+b×b)÷2-ab=(a-b)^2÷2=25÷2=12.5

1-2（a+ab）+（ab-2b）=1-2(a+b)-ab=1-2A-A-2008=3A,A=-669/2,所以a+b=-669/2,ab=-3347/2☆⌒_⌒☆诚心为您解答每一个问题!您的好评是我

a-b-3ab=0a-b=3ab(2a+3ab-2b)/(a-ab-b)=[2(a-b)+3ab]/(a-b-ab)=9ab/2ab=9/2

ab/a+b=3ab=3（a+b）2ab/a+b-5(a+b)/ab=6(a+b)/(a+b)-5(a+b)/3(a+b)=6-5/3=13/3

ab/（a+b）=3,a+b=ab/3原式=[3(a+b)+ab]/[2(a+b)-ab]=[3(ab/3)+ab]/[2(ab/3)-ab]=2ab/(-ab/3)=-6

A+B=7,且AB=3,求A,

(A-B)^2=(A+B)^2-4AB=49-12=37A=(7+根号37）/2B==(7-根号37）/2

a+b=3ab2a+2b-ab=6ab-ab=5aba+b+2ab=5ab所以原式=1