已知{3x 2t=4{2y-t=3-搜答案-智慧作业帮

x=(√3/2)(2t)；y=2-(2t)/2,令2t=T,则X=√3T/2,y=2-T/2,则|T|表示直线上任一点到（0,2）的距离,将X=√3T/2,y=2-T/2代入y^2=2x得：(2-T/

x=1-2t,2t=1-xy=(5-2t)/(7-4t)=[5-(1-x)]/[7-2(1-x)]=(4-x)/(5-2x)x=(5y-4)/(2y-1)

x=y^2-y-2再问：求解答过程再答：y=t-1,t=y+1,代入，x=(y+1)^2-3(y+1)+1=y^2+2y+1-3y-3+1=y^2-y-1检验的时候发现上面回答的错了，答案是y^2-y

将P（3,4t^2）带入x^2+y^2-2(t+3)x+2(1-4t^2)y+16t^4+9

左边的式子乘以2,右面的式子乘以3,相加.最后y=（5-14x）/3

1)x^2+y^2-2(t+3)x+2(1-4t^2)y+16t^4+9=0[x-(t+3)]^2+[y+(1-4t^2)]^2=-7t^2+6t+1R^2=-7t^2+6t+1-7t^2+6t+1>

由x=1-t/2+t得t=2(x-1)将其代入y=5+4t/3-2t得y=5-4(x-1)/3

=[1,0,-1];a=[1,4,6,2];[Hjw,w]=freqs(b,a);

根据题意得配方得：(x-t-3)^2+(y+1-4t^2)^2=-(7t+1)(t-1)-(7t+1)(t-1)>0-1/7＜t＜1配方：[x-(t+3)]^2+[y+(1-4t^2)]^2=(t+3

①x2+y2-2(t+3)x+2(1-4t2)y+16t4+9=0[x-(t+3)]^2+[y+(1-4t^2)]^2=-16t^4-9+(t+3)^2+(1-4t^2)^2则-16t^4-9+(t+

x+y-2（t+3）x+2（1-4t）y+16t^4+9=0(x-(t+3))+(y+(1-4t))+16t^4+9=(t+3)+(1-4t)(x-(t+3))+(y+(1-4t))+16t^4+9=

1.由x=2t+3得,t=(x-3)/2由y=3t-1得,t=(y+1)/3所以(x-3)/2=(y+1)/3解之得y=1.5x-5.52.因为xy的解相同所以x=y=1/5所以1/5m+1/5(m+

这是参数方程求导dy/dx=(dy/dt)(dt/dx)=(dy/dt)/(dx/dt)=(t^3-3t)`/(3t^4+6t)`=(3t^2-3)/(12t^3+6)

y=2x-8.再问：过程........再答：t=（x-3）/2,y=4（（x-3）/2-2,=2x-8

3x+4y=2t.[1]2x+3y=t-1.[2][1]*3:9x+12y=6t[2]*4:8x+12y=4t-4二式相减得：x=2t+4y=(2t-3x)/4=(2t-6t-12)/4=-t-3x

由柯西不等式可知,[(4/5)+(9/4)+(1/3)]×[5(x-y)²+4(y-z)²+3t²]≥[2(x-y)+3(y-z)+t]²=(2x+y-3z+y

x=3t+1t=(x-1)/3y=2t-1=(2x-5)/3

由y+2=3t得y=3t-2又由2x=3-t得t=3-2x所以y=7-6x