已知x=100,y=10求x的平方 2xy y的平方分之x的平方-y的平方的值-搜答案-智慧作业帮

令x=y+3变成x-y=3把x-y=3带到x-y里4分之一(x-y)的平方-0.3(x-y)+0.75(x-y)的平方+10分之3(x-y=2.25-0.9+6.75+0.9=9

x=y+3∴x-y=34分之一(x-y)的平方-0.3(x-y)+0.75(x-y)的平方+10分之3(x-y）-2（x-y）+7=(0.25+0.75)(x-y)²+(-0.3+0.3-2

2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]

你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=（x平方-y平方）/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24

X+y=10,XY=24,则X=4,Y=6或X=6,Y=4,所以(X-Y)(X-Y)=2*2=4或（-2）*（-2）=4,都为4

(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19

|x|+x+y=10|y|+x-y=12两式相加得|x|+|y|+2x=22.(1)两式相减得|x|-|y|+2y=-2.(2)所以-|y|+2y＜0若y＞0,则显然-y+2y＜0,即y＜0,矛盾若y

x²+25+√(y+4)=10xx²-10x+25+√(y+4)=0(x-5)²+√(y+4)=0x=5,y=-4(x+y)^(1/3)=(5-4)^(1/3)=1答：1

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

x²+y²=19(x+y)²=x²+y²+2xy=25xy=3(x-y)*(x-y)=(x-y)²=x²+y²-2xy=

x²＋y²－10x－6y＋34=0,即(x－5)²＋(y－3)²=0,所以,x=5,y=3,所以(x＋y)/y=(5＋3)/3=8/3

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2

（1）x^2+y^2-4x+10y+29=0x^2-4x+4+y^2+10y+25=0(x-2)^2+(y+5)^2=0x=2y=-5剩下的自己解下面两个题目是不是写错了,没看懂

x+y/y=11/8说明11y=8（x+y）即8x=3y所以x-y/x+2y=3（x-y）/3(x+2y)=（3x-3y）/(3x+6y)=(3x-8x)/(3x+16x)=-5/19

x^2+y^2-10x-12y+61=0(x²－10x＋25)＋(y²－12y＋36)=0(x－5)²＋(y－6)²=0因为(x－5)²与(y－6)&

x+y=10平方x²+y²+2xy=100x³+y³=(x+y)(x²-xy+y²)所以x²-xy+y²=100/10=

原式化简=x＋2y=2011

绝对值项恒非负,两绝对值项之和=0,两绝对值项分别=03x-y=0(1)x+y=0(2)(1)+(2)4x=0x=0,代入(2)y=-x=0(x-y)/(xy)无意义,因此题目错了.

4x^2+y-4x-6y+10=0(2x-1)^2+(y-3)^2=0x=1/2y=3y/x-x/y=6-1/6=35/6