已知mn不等于0 n的平分+4m大于0 a不等于b-搜答案-智慧作业帮

(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同类项=-2mn+3m-3n=-2mn+3(m-n)把m-n=2,

由题意得m+1=-1/(n-1)两边同乘n-1得mn-m+n=0两边同除mn得1-1/n+1/m=0则1/m-1/n=-1

解m=3n,mn≠0∴(m²-n²)/(m²-mn-n²)=(9n²-n²)/(9n²-3n²-n²)=8n&

你的做法很好,还可以这样做：假设m/n=t,要求的就是t-1/t的值,已知的就是t+1/t=4.只要把t+1/t=4平方,则有t²+1/t²+2＝16,所以t²+1/t&

m^2=n+2,①n²=m+2,②①-②,得,m²-n²=n-m(m-n)(m+n)=n-m因为m≠n所以m-n≠0,两边除以m-n,得,所以m+n=-1①*②,（mn）

解（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn）=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=-2mn-3mn-mn+2m+2m-m+3n-2n-4n=-6mn+3

∵m,n是方程x的平方加mx加n等于0的两个实数根∴m+n=-m,m·n=n,∴n=-2m,m=1,∴n=-2,m=1,

m3-3mn+n3=(m2)*m-3mn+(n2)*n=(n+2)m-3mn+(m+2)n=mn+2m-3mn+mn+2n=2(m+n)-mn又因为m2=n+2,n2=m+2相减得到：m2-n2=(m

1求交点,则m/|x|＝n|x|;x^2=m/n∵mn>0∴m/n=mn/n^2>0.∴x=±√(m/n).此时|y|=m/|x|＝n|x|=n·√(m/n)=√(mn).y=±√(mn).即(-√(

-2mn+2m+3n-3mn-2n+2m-4n-m-mn=-6mn+3m-3n=-6mn+3(m-n)=6+9=15

根据题意绝对值和完全平方非负所以mn-1=0m-n-2=0mn=1m-n=2（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-m

m2=n+2n2=m+2相减m2-n2=n+2-m-2(m+n)(m-n)=-(m-n)m-n≠0两边除以m-nm+n=1不好意思写错了(m+n)(m-n)=-(m-n)两边除以m-nm+n=-1

原式=-2mn+2m+3n-3mn-2n+2n-m-4n-mn=-6mn+m-n=-6×2+4=-8

解答如下m^3-2mn+n^3=m(m^2-2n)+n^3=m(2-n)+n(m+2)=2m-mn+mn+2n=2(n+m)m^2=n+2,n^2=m+2相减：(m+n)(m-n)=-(m-n)m≠n

再问：用不用写|m|/m=＋－1，n/|n|=＋－1再答：不用写，各种情况已经全部考虑到了

m^3-4mn+n^3=m(2n+5)-4mn+n(2m+5)=5m+5nm^2=2n+5,n^2=2m+5两个相减得m^2-n^2=2(m-n)因为m不等于nm+n=2所以上边得是10

(-m-4n-mn)-(2mn-2m-3n)-(3mn+2n-2m)=-m-4n-mn-2mn+2m+3n-3mn-2n+2m=3m-3n-6mn=3(m-n)-6mn=3×3-6×(-3)=9+18

m²=n+2；n²=m+2；m²n²=mn+4+2(m+n);m²n²-mn-2=0;(mn-2)(mn+1)=0;mn=2或mn=-1；m