已知cos(α π 6)=4 5,α为锐角

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已知cosα=1/3,α属于(π,2π),则cosπ/2等于

cosπ/2=0与角α无关是求coaα/2吧∵cosα=1/3根据二倍角公式:cosα=2(cosα/2)^2-1∴(cosα/2)^2=(1+cosα)/2=2/3∵α属于(π,2π)∴α/2属于(

已知tan²=3,求3cos²α-2sinα×cosα-4cos²α-6

原式=3cos²α-2sinα×cosα-4cos²α-6(sin²α+cos²α)=-6sin²α-2sinαcosα-7cos²α=(-

已知cos(α-π6

∵cos(α-π6)+sinα=32cosα+32sinα=453,∴12cosα+32sinα=45,∴sin(α+7π6)=-sin(α+π6)=-(32sinα+12cosα)=-45.故答案为

(文)已知cosα=-45

∵cosα=-45,且α为第三象限角,∴sinα=-1−cos2α=-35,则tanα=sinαcosα=34.

已知sinα-cosα=1/5,且π

sinα-cosα=1/5,则有(sinα-cosα)^2=1/25即(sinα)^2+(cosα)^2-2sinαcosα=1/25sin2α=1-1/25=24/25cos2α=√(1-(sin2

已知sinα+cosα=1 证明(sinα)^6+(cosα)^6=1

sinα+cosα=1==>sin²x+2sinxcosx+cos²x=1sinxcosx=0所以sinx=0或cosx=0,cosx=±1或sinx==±1(sinα)^6+(c

已知cos(α+β)=513 ,cosβ=45

由cos(α+β)=513,cosβ=45,根据α,β∈(0,π2),得到α+β∈(0,π),所以sin(α+β)=1-(513)2=1213,sinβ=1-(45)2=35,则sinα=sin[(α

已知cos(π\3-2)=1\3,则cosα+根号3sinα=

cos(π/3-α)=1/3cosπ/3cosα+sinπ/3sinα=1/3(1/2)cosα+√3/2sinα=1/3cosα+√3sinα=2/3

已知cos(π6+α)=33

∵cos(π6+α)=33,∴cos(5π6-α)=cos[π-(π6+α)]=-cos(π6+α)=-33.故答案为:-33

已知cosα=负5分之3,π

上面的等于5分支9,把括号拆开,整理等于1--sina,因为cosa等图-3/5,所以sina=-4/5下面的等于25分支17,把sin4a变成sin2a(1--cos2a),同理改cos4a,最后再

已知α为锐角,且cos(α+π6)=45,则cosα的值为(  )

∵α为锐角,且cos(α+π6)=45,∴sin(α+π6)=35,∴cosα=cos[(α+π6)-π6]=cos(α+π6)cosπ6+sin(α+π6)sinπ6=45•32+35•12=43+

已知sinα-cosα=-根号5/5,π

sinα-cosα=-根号5/5π

已知α为锐角,且cos(α+π/6)=5/13,求cosα的值

cos(a+π/6)=5/13那么sin(a+π/6)=12/13cos(a+π/6)=cosa*cos(π/6)-sina*sin(π/6)=5/13sin(a+π/6)=cosa*sin(π/6)

已知1+cosα/cosα=-1/2求cosα/sinα-1

解题思路:利用三角函数公式求解解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/re

已知tan(π+α)=a²,|cos(π-α)|=-cosα,求1/[cos(π+α)]的值

|cos(π-α)|=-cosα>0所以cos(π+α)=-cosα>0tan(π+α)=a²=sin(π+α)/cos(π+α)>=0所以sin(π+α)0因此1/[cos(π+α)]=(

已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为

[cos^4(π/3+α)]-[cos(π/6-α)]^2=[cos(π/3+α)]^4-[sin(π/3+α)]^4=[cos(π/3+α)]^2-[sin(π/3+α)]^2=cos(2π/3+2

已知cos(π/6-α)=根号3/3,求cos(5π/6+α)的值

因为cos(5π/6+α)=cos[π-(π/6-α)]=-cos(π/6-α),又因为cos(π/6-α)=√3/3,所以:cos(5π/6+α)=-√3/3