已知cos(75° x)=1 3,x为第三象限角

f(x)=cos(-2x+a)(-π

根据公式：COS^2a=(1+COS2a)/2a=(X+π/12)说句不好听的,你还是基本知识没掌握好,不会活用知识.希望你多背多看,看清题,把公式活用.

题目是否为cos(-255度-x)+sin(435+x)cos(-255度-x)+sin(435+x)=cos(255度+x)+sin(75度+x)=-cos(75度+x)+sin(75度+x)又co

f(x)=sin2x+2cos²x-1+1=sin2x+cos2x+1=√2(√2/2*sin2x+√2/2cos2x)+1=√2(sin2xzosπ/4+cos2xsinπ/4)+1=√2

整理方程,得y=1+2sinxcosx+2(cosx)^2利用降幂公式和二倍角公式,得y=sin2x+cos2x+2再利用辅助角公式,得y=根号2*sin(2x+π/4)+2所以当2x+π/4属于[2

∵cos（x-π/6）=-√3/3∴cosx+cos（x-π/3）=cosx+cosxcosπ/3+sinxsinπ/3=cosx+（1/2）cosx+（√3/2）sinx=（3/2）cosx+（√3

已知0＜x＜π/4,sin(π/4-x)=5/13,求cos2x/cos(π/4+x)的值已知0＜x＜π/4,则sinx>0,cosx>0sin(π/4-x)=sinπ/4·cosx-cosπ/4·s

cos（23π/6-x）=cos[-(x-23π/6)]=cos[-(x+13π/6-6π)]=cos[-(x+13π/6)+6π]=cos（13π/6+x）=根3/3

∵α是第三象限角，∴k•360°+255°＜α+75°＜k•360°+345°（k∈Z），∵cos(75°+α)＝13，∴α+75°是第四象限角，∴sin(75°+α)＝−1−(13)2＝−223，∴

f'(x)=-1/2*sin(x/2)*[sin(x/2)-cos(x/2)]+cos(x/2)[1/2cos(x/2)+1/2sin(x/2)]=-1/2*sin²(x/2)+1/2sin

f(x)=cos(2x-π/3)-(cos^2x-sin^2x)=cos(2x-π/3)-cos2x=2sin(2x-π/6)sinπ/6=sin(2x-π/6)因为y=sinx的单减区间为[π/2+

f(x)=cos(2x-π\3)+sin²x-cos²x=1/2cos2x+√3/2sin2x-cos2x=√3/2sin2x-1/2cos2x=-cos(2x+π\3)-1

cos(105度-x)=-cos(180-105+x)=-cos(75+x)=-1/31/3=cos（75+x)=sin(90-75-x)=sin(15-x)=-sin(x-15)所以sin(x-15

cos2x=3/5,sin2x=±4/5sin^4x+cos^4x=（-sinx^2+cosx^2)^2+2sinx^2cosx^2=cos2x^2+1/2sin2x=9/25±2/5=19/25,或

你确定第一个符号是加号不是乘号?

已知f(cosx)=cos3x,则f(sinx)=要有过程sinx=cos(π/2-x)f(sinx)=f(cos(π/2-x))=cos3(π/2-x)=sin3x

sinx=2cosx,sin^2x=4cos^2xsin^2x=4-4sin^2x,sin^2x=4/5(cosx+sinx)/(cosx-sinx)+sin^2x=(1+tanx)/(1-tanx)

f(x)=2cosx*sinx-2cosx^2+1f(x)=sin2x-cos2xf(x)=根号2*sin(2x-45)周期T=π

解由90°

∵已知cos(75°+α)=13，∴sin（15°-α）=13，则cos（30°-2α）=1-2sin2（15°-α）=79，故答案为79．