已知A^2-3A 2E=0,A的行列式为2,求(A E)^(-1)的行列式为多少

a^5-5a+3=a³﹙a²＋a-1﹚－a^4＋a³-5a+3=a³﹙a²＋a-1﹚－a²﹙a²＋a-1﹚＋2a³-a&

3a^3+(a^2+5)(a^2-1)-5(a+1)(a-1)-6a=a^4+3a^3-a^2-6a=a^4+3a^3+a^2-2a^2-6a=a^2(a^2+3a+1)-2a^2-6a=-2a^2-

A^2+A-1=0,A^2+A=1A^3+2A^2+3=A(A^2+A+A)+3=A(1+A)+3=A^2+A+3=1+3(m-n-1)^2=(m-n)^2-2(m-n)+1=m^2-2mn+n^2-

a三次方-2a+3=a³-a²-a+a²-a-1+4=a(a²-a-1)+(a²-a-1)+4=0+0+4=4

解a²-3a+1=0两边除以a得：a-3+1/a=0∴a+1/a=3两边平方a²+1/a²+2=9∴a²+1/a²=9-2=7

爱的繁体∵a^2+a-1=0∴a^2+a=1a^3+2a^2-2009=(a^3+a^2)+a^2-2009=a(a^2+a)+a^2-2009=a+a^2-2009=(a+a^2)-2009=1-2

a+a^2+a^3+a^4+.+a^2004=a(1+a+a^2+a^3)+a^5(1+a+a^2+a^3)+.+a^2001(1+a+a^2+a^3)=0

a^2-a-1=0,∴a²-a=1∴a^3-2a+2010=a³-a²+a²-2a+2010=a(a²-a)+a²-2a+2010=a+a&

a^2+a-1=0a^2+a=1a^3+2a^2+1999=a^2+a^2+a^2+1999=a(a^2+a)+a^2+1999=a++a^2+1999=1+1999=2000

a^2-3a-1=0a^2-3a=1原式=a^3-3a^2+3a^2-9a-a=a(a^2-3a)+3(a^2-3a)-a=a+3-a=3

a²=a+1所以a⁴=(a²)²=(a+1)²=a²+2a+1=(a+1)+2a+1=3a+2所以原式=3a+2-3a+2=4

a^2+1=3a两边除以aa+1/a=3平方a^2+2+1/a^2=9a^2+1/a^2=7(a-1/a)^2=a^2-2+1/a^2=7-2=5(a^2-1/a^2)(a-1/a)=(a+1/a)(

由题目知道a^3+a^2=a,a^2+a=1上面两个式子相加得a^3+2a^2=1所以a^3+2a^2+3=1+3=4

a^2+a+1=01+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8=a^2+a+1+a^3*(a^2+a+1)+a^6*(a^2+a+1)=0

a^3+a^2+a+1=0a^2(a+1)+(a+1)=0(a+1)(a^2+1)=0所以a+1=0即a=-1a^2007+a^2008+a^2009+a^2010+a^2011=-1+1-1+1-1

a^2+a-1=0,a^2+a+1=2两边同乘以(a-1)(a-1)(a^2+a+1)=2(a-1)a^3-1=2a-2a^3-2a=-13a^3-6a+3=3(a^3-2a)+3=3×(-1)+3=

a*a+4a+1=0；a^2+1=-4aa^4+1+2a^2=(-4a)^2=16a^2a^4+1=14a^22a^3+2a=-8a^2(a*a*a*a-ma*a+1)/(2a*a*a+ma*a+2a

1+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8=1+a+a^2+a^3(1+a+a^2)+a^6(1+a+a^2)=(1+a^3+a^6)(1+a+a^2)=0

a-2a-4=0==>A^2-A=A+4==>A^2-2A=4==>A^2=4+2A所以a-[a-1/(1-a)]/[(a-a+1)/(a-2a+1)]*1/(a-1)=A-[(A-A^2-1)/(1

解原式=4a²-2(a²-a+3)-1/2(a²-a-4)-4a=4a²-2a²+2a-6-1/2a²+1/2a+2-4a=3/2a