9m²-9n² 6m 1

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点M(4,m)关于点N(n,-3)的对称点为P(6,9)求m,n

点M(4,m)关于点N(n,-3)的对称点为P(6,9)所以有:4+6=2n,m+9=2*(-3)得:n=5,m=-15

(m的平方-6mn+9n的平方)÷(m-3n)-(4m的平方-9n的平方)÷(2m-3n)=

(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)÷(2m-3n)=(m-3n)²÷(m-3n)-(2m-3n)(2m+3n)÷(2m-3n)

(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)÷(2m-3n)化简,

(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)÷(2m-3n)=(m-3n)^2÷(m-3n)-(2m+3n)(2m-3n)÷(2m-3n)=m-3

9m²-6m+2n-n²(因式分解,

9m²-6m+2n-n²=9m²-n²-6m+2n=(3m-n)(3m+n)-2(3m-n)=(3m-n)(3m+n-2)

(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)-(2m-3n)怎么做

(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)÷(2m-3n)=(m-3n)^2÷(m-3n)-(2m+3n)(2m-3n)÷(2m-3n)=m-3

已知m^2+9n^2+4m-6n+5=0,求m,n的值

m^2+9n^2+4m-6n+5=0,m^2+4m+4+9n^2-6n+1=0,(m+2)²+(3n-1)²=0,(m+2)²>=0,(3n-1)²>=0,所以

M(x,y)到定点M1,M2距离之比为n,求M的轨迹~

当n=1时,所求轨迹即为M1,M2二点连线的中垂线.当n≠1时,轨迹为一个圆,称为Apollonius圆(阿波罗尼乌(奥)斯圆、阿氏圆),是著名轨迹之一.在M1与M2的连线段上取一点A,使得M1A=n

(m+n)²-6(m+n)+9

(m+n)2-6(m+n)+9=(m+n-3)2

已知2m-3n/3m+n=2,求4m-6n/9m+3n+18m+6n/4m-6n的值

已知(2m-3n)/(3m+n)=2,所以(4m-6n)/(9m+3n)=2/3*(2m-3n)/(3m+n)=2/3*2=4/3(18m+6n)/(4m-6n)=6/2*1/2=3/2所以(4m-6

(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^

(3m-2n)²+(3m+2n)(3m-2n)-9(m+n)²=(3m-2n)²-9(m+n)²+(3m+2n)(3m-2n)=(3m-2n+3m+3n)(3m

(m+2n)-6(m+2n)(2m-n)+9(n-2m) 因式分解

(m+2n)-6(m+2n)(2m-n)+9(n-2m)=[m+2n+3(n-2m)]^2=(5n-5m)^2=25(n-m)^2

(m+n)²-6(m+n)+9=(m+n)²+2(m+n)×(-3)+(-3)²=[(m+

将m+n看作x,那么算式变成了x的方-6x+9,那么用平方公式一算,就是(x-3)的方,所以答案不就是(m+n-3)的方嘛!至于-3嘛,-3乘以2不就是-6嘛!希望采纳,谢谢!

若(m-2n)/(2m+n)=3,则[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)] - {9(m-2n

(m-2n)/(2m+n)=3m-2n=6m+3n5m+5n=0m=-n[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)]-{9(m-2n)/[4(2m+n)]}=[3(-n-2n)/(

已知2m-3n/3m+n=2 求(4m-6n/9m+3n)+(18m+6n/4m-6n)的值.要有步骤和讲解.

2m-3n/3m+n=2,则2m-3n=6m+2n4m=-5nm=-5n/4所以(4m-6n/9m+3n)+(18m+6n/4m-6n)=[(-5n-6n)/(3n-45n/4)]+(6n-45n/2

若m²+2m+n²-6n+9=0,求m和n的值.m²

x²+5y²-4xy+2y+1=0x²+4y²-4xy+y²+2y+1=0(x-2y)^2+(y+1)^2=0∵(x-2y)^2>=0,(y+1)^2

2m-3n/3m+5n=3 则(4m-6n/18m+30n)+9m+15n/4m-6n的值是多少

2m-3n/3m+5n=3则:3m+5n/2m-3n=1/3(4m-6n/18m+30n)+9m+15n/4m-6n=2(2m+3n)/6(3m+5n)+3(3m+5n)/2(2m-3n)=1/3*3

-(m+n)^2+6(m+n)-9

-(m+n)^2+6(m+n)-9=-[(m+n)^2-6(m+n)+9]=-[(m+n)-3]^2=-(m+n-3)^2再问:谢谢,但还有一道再答:2a^3b-4a^2b^2+2ab^3=2ab(a

(m+n)^2+6(m^2-n^2)=9(m-n)^2

=是不是+?原式=(m+n)²+6(m+n)(m-n)+[3(m-n)]²=[(m+n)+3(m-n)]²=(4m-2n)²=4(2m-n)²

1/2(m-n)+1/4(m+n)+m+n/3-m-n/6 其中m=-9 n=-3

1/2(m-n)+1/4(m+n)+m+n/3-m-n/6=1/2m-1/2n+1/4m+1/4n+m+n/3-m-n/6=(1/2m+1/4m+m-m)+[(-1/2n+1/4n)+(n/3-n/6