9log4 = - 3 2a maka 1 4 log 27 adalah

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/25 11:17:28
log3 7·log2 9·log49 a=log4 1/2,则a=

若log37·log29·log49a=log41/2,则有:(lg7/lg3)·(lg9/lg2)·(lga/lg49)=lg(1/2)/lg4即:(lg7/lg3)·(2lg3/lg2)·lga/

(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?

=(log(2,3)/2+log(2,3)/3)*(log(3,2)+1/3-?)log(a,b)=ln(b)/ln(a)

log2^x=log4^9

log2^x=log4^9=log2^2(3^2)=log2^3所以x=3

log4(log2^x)=log2(log4^x)求log2^x

如果log4(log2^x)是表示外面的log以4为底,而里面的log以10或其它数(>0)为底的话,则log4(log2^x)=[log2(log2^x)]/2=log2(log4^x)=log2(

log4(3x-1)-log4(3+x)=log4(x-1)

答:log4(3x-1)-log4(3+x)=log4(x-1)log4(3x-1)=log4(3+x)+log4(x-1)3x-1=(3+x)(x-1)3x-1=3x-3+x²-xx

log4

log436=log26=log2[2*3]=1+log23logxy=logx[n]y[n]log436=log4[1/2]36[1/2]

已知4^a=3 代数式log8(9)-2^(log4(3))

a=log4(3)=lg3/lg4所以lg3=alg4=2alg2log8(9)=lg9/lg8=2lg3/3lg2=4alg2/3lg2=4a/3log4(3)=lg3/2lg2=(1/2)*log

计算:log27(32)×log64(27)+log9(2)×log4(√27)=

原式=[(5lg2/3lg3)*(3lg3/6lg2)]+{(lg2/2lg3)*[(3/2)lg3/2lg2]}=(5/3)+(3/8)=49/24再问:不是应该算的5/6+3/8=29/24?再答

log4 8-log1/9 3=log 根号2 1/4怎么算

log48-log1/93=log根号21/4lg8/lg4-lg3/lg(1/9)=3lg2/2lg2-lg3/-2lg3=3/2+1/2=2log根号21/4=lg(1/4)/lg根号2=-2lg

解方程 log4 (3x-1)=log4 (x-1)+log4 (3+x)

log4(3x-1)=log4(x-1)+log4(3+x)log4(3x-1)=log4[(x-1)(3+x)]3x-1=x²+2x-3x²-x-2=0(x+1)(x-2)=0x

2^log4^3=?

原式=(4^0.5)^log4(3)=4^0.5log4(3)=4^log4(3^0.5)=4^log4(√3)=√3

log4 8-log8 4=?

log48=log2^22^3=log22^(3/2)=3/2所以:log84=2/3;所以:log48-log84=3/2-2/3=5/6.

log1/4(x+3)-log4(x-1)=log1/4(x+9)?

log1/4(x+3)-log4(x-1)=log1/4(x+9)lg(x+3)/lg1/4-lg(x-1)/lg4=lg(x+9)/lg1/4lg(x+3)/-lg4-lg(x-1)/lg4=lg(

log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(

这个问题是这样的4=2²=(2^3)^(2/3)=8^(2/3)所以log8(8^(2/3))=2/3前面的是对数运算法则logaM-logaN=loga(M/N)

已知log2^3=a则log4^9=

因为log2^3=a所以log4^9=log(2^2)^3*3=log(2^3)^3*2=3*2log2^3=6a

log4 243 - log8 729=?log4 12 - log2 6=?

=lg243/lg4-lg729/lg8=5lg3/2lg2-6lg3/3lg2=5lg3/2lg2-4lg3/2lg2=lg3/lg4=log4(3)原式=lg12/lg4-lg6/lg2=(2lg

对数函数log4 x+log4 (64x²) =6

即log4(x*64x²)=log4(4^6)所以64x³=4^6x³=64x=4