56-x的平方
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﹙x+y)²-﹙x+y)-56=(x+y+7)(x+y-8)用十字相乘法x+y+7x+y-8
原式=(x^2-7x+6)(x^2-x-6)+56=(x-6)(x-1)(x-3)(x+2)+56=[(x-6)(x+2)][(x-1)(x-3)]+56=(x^2-4x-12)(x^2-4x+3)+
1)-4x^3-16x^2-26x=-2x(2x^2+8x+13)2)56x^3yz+14x^2y^2z-21xy^2z^2=7xyz(8x^2+2xy-3yz)
得到:X^2-15X=-56X^2-15X+56=0(x-7)(x-8)=0所以X=7或者x=8
答:原式=(x^2-7x+6)(x^2-x-6)+56=(x-6)(x-1)(x-3)(x+2)+56=[(x-6)(x+2)][(x-1)(x-3)]+56=(x^2-4x-12)(x^2-4x+3
1.无解2.任意实数
(X的平方+9x)/(x的平方+3x)+(x的平方-9)/(x的平方+6x+9)=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)²=(x+9)/(x+3)+(x-3)/(x+3
1.2x^2+2x=2x(x+1)=0x=0或x=-12.x^2-2x+1=(x-1)^2=0x=13.x的平方-57x+56=(x-1)(x-56)=0x=1或x=564.(x-1)的平方+3(x-
(x平方+y平方)平方-y平方=x平方+6所以(x²+y²)²-(x²+y²)-6=0(x²+y²+2)(x²+y
x=-8,+7由x的平方=x+56得(x-8)(x+7)=0
原式=(x+1)²(x-1)²-4(x+1)²=(x+1)²[(x-1)²-4]=(x+1)²(x-1+2)(x-1-2)=(x+1)&su
因式分解得(x-8)(x+7)=0所以x=8orx=-7
(x的平方+9)的平方-36x的平方=(x^2+6x+9)(x^2-6x+9)=(x+3)^2(x-3)^2
x=8x^2-x=56x^2-x+1/4=56+1/4(两边各加1/4)(x-1/2)^2=225/4x-1/2=15/2x=16/2x=8
=(x+7)(x+8)
xy=8x^2y-xy^2-x+y=568x-8y-x+y=567x-7y=56x-y=8x^2+y^2=(x-y)^2+2xy=8^2+2*8=64+16=80所以,x^2+y^2=80
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
解(x²-x+2)(x²-2)=x^4-2x²-x³+2x+2x²-4=x^4-x³+2x-4
x²=x+56x²-x-56=0(x-8)(x+7)=0x=8或x=-7
(x的平方-4x-12)(x的平方-4x+3)+56=(x²-4x)²-9(x²-4x)-36+56=(x²-4x)²-9(x²-4x)+2