5-6x＝17-9x

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

（3x+5)/(x+2)=[(3x+6)-1]/(x+2)=3-1/(x+2)后面都类似化简3-1/(x+2)+3-1/(x+9)=3-1/(x+6)+3-1/(x+5)1/(x+2)+1/(x+9)

方法一：就是直接通分.方法二：个人觉得算是比较简单的方法,省去了化简乘式的繁琐.见下：（x-4)/(x-5)=1+1/(x-5)以下同此化简可得式：1+1/(x-5)+1+1/(x-9)-[1+1/(

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

 再问：额、不懂再答： 再答：后面的看做一个整体再问：好的吧、谢谢大神再答：回来的话，请采纳再问：啊、突然明白了呢。。。

[1-1/(x-4)]+[1-1/(x-8)]=[1-1/(x-7)]+[1-1/(x-5)]1/(x-4)+1/(x-8)=1/(x-7)+1/(x-5)(x-4+x-8)/(x-4)(x-8)=(

(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(x+

1.(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

15x=23x-248x=24x=312+5x=3x-82x=-20x=-103(x-3)=9-(x+6)4x=9+9-6=12x=34+x=4x-173x=21x=7

/>因为：x-5/x-6+x-8/x-9=x-7/x-8+x-6/x-7,所以：1+1/(x-6)+1+1/(x-9)=1+1/(x-8)+1+1/(x-7)即：1/(x-6）+1/(x-9)=1/(

(1)(X+7)/(X+6)+(X+9)/(X+8)=(X+10)/(X+9)+(X+6)/(X+5)这类方程重在运算的技巧性,观察分母7+9=10+6;6+8=5+9所以先移项:(X+7)/(X+6

即1/(x-5)+1/(x-9)=1/(x-6)+1/(x-8)(2x-14)[1/(x-5)(x-9)-1/(x-6)(x-8)]=01/(x-5)(x-9)-1/(x-6)(x-8)≠0所以2x-

主要是考察因式分解这方面的技能啊![(2x²-5x+2)/(6x²+13x+6)]*[(6x²-5x-6)/(6x²-17x+10)]*[(12x²+

这道题不用那么复杂.先移项.(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/( x-9)再通分.（x-4)(x-6)/(x-5)(x-6)-(x-5)(x

左右两边同乘以(X-5)(X-6)(X-8)(X-9)得到(X-4)(X-6)(X-8)(X-9)-(X-5)(X-5)(X-8)(X-9)=(X-5)(X-6)(X-7)(X-9)-(X-5)(X-

x=123/14

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(X-4)/(X-5)-(X-5)/(X-6)=(X-7)/(X-8)-(X-8)/(X-9)[(x-4)(x-6)-(x-5)2]/(x-5)(x-6)=[(x-7)(x-9)-(x-8)2]/(x