4x的平方-1 4y的平方分解因式-搜答案-智慧作业帮

解法一用双十字相乘法分解x^2-2xy-8y^2-x-14y-6=(x^2-2xy-8y^2)-x-14y-6=(x-4y)(x+2y)-(x+14y)-6=[(x-4y)-3][(x+2y)+2]=

原式=-y(4x²-4xy+y²)=-y(2x-y)²

3x^2+5xy-2y^2+x+9y-4=(3x-y)(x+2y)+4x+8y-3x+y-4={(3x-y)+4}(x+2y)-3x+y-4=(3x-y+4)(x+2y-1)

4(x+2y)²-9(x-y)²=[2(x+2y)]²-[3(x-y)]²=[2(x+2y)+3(x-y)][2(x+2y)-3(x-y)]=(5x+y)(-x

xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+

4xy的平方-4x的平方y-y的三次方=y(4xy-4x^2-y^2)=-y(4x^2-4xy+y^2)=-y(2x-y)^2

3x的4次方+x的平方y-2y的平方=(x²+y)(3x²-2y)很高兴为您解答,【the1900】团队为您答题.请点击下面的【选为满意回答】按钮,再问：有过程吗，如果是一步的话有

把x+y当做一个因子,7当做一个因子（x+y）^2-14(x+y)+49=（x+y）^2-2*7*(x+y)+7^2=(x+y-7)^2

题目有问题吧,我感觉应该是(x²+y²-z²)²-4x²y²(x²+y²-z²)²-4x²

1.原式=（3x+4y）[3x+4y-3x]/(-4y)=(3x+4y)[4y]/(-4y)=-(3x+4y)=-3x-4y2.原式=[(3a-3b)-(2a+2b)][(3a-3b)+(2a+2b)

3x²+5xy-2y²+x+9y-4=(3x-y)(x+2y)+x+9y-4=(3x-y+4)(x+2y-1)用二次十字相乘法：(1)3x²+5xy-2y²=(

y^2-x^2=(y+x)(y-x)

=(x^2-4)^2-y^2=(x^2-4+y)(x^2-4-y)

原式=(a²+b²+2ab)(a²+b²-2ab)=(a+b)²(a-b)²原式=a²(x-y)-b²(x-y)=(x-

=[(x+y)-2y]²=(x-y)²

x²-4y²=x²-（2y）²=（x+2y）（x-2y）这里用到了平方差公式.很高兴为您解答,祝你学习进步!如果我的回答对你有帮助,请及时选为满意答案,谢谢~~

(x²+16y²)²-64x²y²=(x²+16y²)²-(8xy)²=(x²+16y²+

(x^2+4y^2)^2-16x^2y^2＝(x+4y)-(4xy)=(x+4y+4xy)(x+4y-4xy)=(x+2y)(x-2y)请采纳回答

（x+y)的平方-6x的平方+6y的平方+9(x-y)的平方=(x+y)²-6(x²-y²)+9(x-y)²=(x+y)²-6(x+y)(x-y)+9