在-1到1之间产生随机矩阵-搜答案-智慧作业帮

在B1输入=IF(A1=1,INT(RAND()*59+700),IF(A1=2,A1*400,""))

2*rand(n)-1

sheet2的A1留空B1输入公式=SMALL(IF(COUNTIF(A$1:A1,ROW($1:$34)-1),65536,ROW($1:$34)-1),ROUNDUP(RAND()*(34-COL

先在窗体上添加一个TextBox文本框（将其Multiline属性设置为True,并调整宽高以便能较好的显示出100个随机数）和一个Button按钮.然后双击Button按钮跳转到代码编辑窗口,粘帖以

#include <stdio.h>#include <stdlib.h>#include <time.h>int mks(

#include#include#includeintmain(){inta,b,c;srand((unsigned)time(0));a=rand()%100+1;b=rand()%100+1;c=

3+2*rand()

and()*2-1

%生成随机数据clear;clc;a=10*(1:2:9);b=[0,sort(randint(1,4,[1,199])),200];idx=randperm(200);forn=1:5X(idx((

#include"stdio.h"#include"stdlib.h"#include"time.h"intmain(){\x09inti,

你可以用randint(m,n)是生成只有0,1的m*n维矩阵然后randint(m,n).*2-1就可以了例如运行如下程序randint(3,4).*2-1ans=11-11111-1-1-111

复制如下代码到VBA中,运行即可PublicSubgen()DimiAsIntegerDimjAsIntegerDimkAsIntegerDima(25)AsIntegera(0)=Int(Rnd()

ound(rand([1020])*7)+3%不需要整数的话,把round去掉就行了

0,21,20,11,1考虑这四个坐标围成的正方形,总面积=1再画直线x+y=1.5,把其和正方形在左下所围成三角形的面积去掉就是了P(x+y=1.5)=1-1/8=7/8再问：果然是大神果断采纳

#include#include#includevoidmain(void){inti;/*Seedtherandom-numbergeneratorwithcurrenttimesothat*the

0.01*(2*rand(1000,1)-1)

A=0:10;%产生0到10index=randperm(11);%随机生成0-10在数组中的位置A=A(index);%0到10之间的随机数组Ab1=A(A3)%关系运算找到大于3的数A2=A(A3

PrivateSubCommand1_Click()DimiAsInteger,xAsInteger,sAsLongRandomizeFori=1To30x=Int(Rnd*100)+1Printx,

PrivateSubCommand1_Click()Dima,b,cAsIntegerRandomizea=Int(Rnd*9)+1Randomizeb=Int(Rnd*9)+1Randomizec=

#include#includeintmian(void){intarr[50]={0};srand((unsignedint)time(NULL));intnIndex=0;for(;nIndex{