因式分解:X平方[X减Y]加Y平方[Y减X]-搜答案-智慧作业帮

(4x的平方加y的平方）的平方减16x的平方y的平方=(4x^2+y^2)^2-16x^2y^2=16x^4-8x^2y^2+y^4=(4x^2-y^2)^2=(2x+y)^2*(2x-y)^2

25(x+y)²-9(x-y)²　　=[5(x+y)]²-[3(x-y)]²　　=[5(x+y)+3(x-y)][5(x+y)-3(x-y)]　　=(8x+2y

x的平方加2x加1减y的平方=(x+1)²-y²=(x+y+1)(x-y+1)

x^2-4xy+3y^2-x-y-2=(x-y+A)(x-3y+B)=x^2-4xy+3y^2+(A+B)x-(3A+B)y+ABA+B=-13A+B=1AB=-2A=1B=-2所以原式=(x-y+1

x的平方减6xy加9y的平方减2x加6y加1=(x-3y-1)^2

=(x+y)[(x-y)-(x+y)]=(x+y)(x-y-x-y)=-2y(x+y)

x^2-4xy+4y^2-3x+6y+2=(x-2y)^2-3(x-2y)+2=(x-2y-1)(x-2y-2)

(x-y)(x+y-1)

(x-y)(3x+3y)平方差公式

x²y(x-y)-xy²(x-y)=xy(x-y)(x-y)=xy(x-y)²如果不懂,祝学习愉快!

3x的平方减10xy加3y的平方减x减5y减2=3x^2-10xy+3y^2-x-5y-2=(3x-y)(x-3y)-x-5y-2=(3x-y+2)(x-3y-1)提示:两次运用十字相乘

x²-8xy+15y²+2x-6y=(x-3y)(x-5y)+2(x-3y)=(x-3y)(x-5y+2)

/>原式变形得：x²＋yx＋x－6y²＋13y－6=x²＋﹙y＋1﹚x＋﹙3y－2﹚﹙－2y＋3﹚=﹙x＋3y－2﹚﹙x－2y＋3﹚

xy+y平方+x-y-2=xy+x+y^2-y-2=x(y+1)+(y+1)(y-2)=(y+1)(x+y-2)

x^2-y^2+6x+9=x^2+6x+9-y^2=(x+3)^2-y^2=(x+3+y)(x+3-y)再问：那x的平方加y的平方减9的完全平方减4x的平方y的平方怎么因式分解？再答：(x^2+y^2

81(x+y)^2-121(x-y)^2=[9(x+y)-11(x-y)][9(x+y)+11(x-y)]=(9x+9y-11x+9y)(9x+9y+11x-11y)=(18y-2x)(18x-2y)

原式=[(2x+y)-3]²=(2x+y-3)²

稍等再答：x^2-4x+(4-y)^2是这个题目吗？再问：4-y没括号再答：x^2-4x+4-y^2?第二个4不是4y？再问：不是再答：再问：第二个4没有乘方能用完全平方吗？再答：可以啊，中间的4x，

原式=(x-y)²-4(x-y)-12=(x-y-6)(x-y+2)

1+2xy-x^2-y^2=1-(-2xy+x^2+y^2)=1-(x-y)^2=(1-x+y)(1+x-y)