作业帮因式分解:(3x^4 6x^3y^2 3x^2y^4)-3x^4y^2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/28 09:12:53
原式=-(x-y)³(x-y-1)
(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.（x+y）^2-（x+y）^3=（x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、（x
4x^3-4x^2y-(x-y)=4x^2(x-y)-(x-y)=(x-y)(4x^2-1)=(x-y)(2x-1)(2x+1)
（3x+2y)(2x+3y)=3x(2x+3y)+2y(2x+3y)=6x²+9xy+4xy+6y²=6x²+13xy+6y²
=(x-y)²[x+2(x-y)]=(x-y)²(3x-2y)
4x^3-4x^2y-(x-y)=4x²(x-y)-(x-y)=(x-y)（4x²-1）=(x-y)(2x+1)(2x-1)再问：a^3+1/81(b^3)x(x+4)+4x的绝对
(x-y)²-(3x-3xy+y²)=x²+y²-2xy-3x+3xy-y²=x²-3x+xy=x(x+y-3)
x^3+x^2y-xy^2-y^3=（x-y）(x^2+xy+y^2)+xy(x-y)=(x-y)(x^2+y^2+2xy)=(x-y)(x+y)^2
=3（x+y)2
(x-y)^3+(y-z)^3+(z-x)^3=[(x-y)^3+(y-z)^3]+(z-x)^3=(x-y+y-z)[(x-y)^2-(x-y)(y-z)+(y-z)^2]+(z-x)^3=(x-z
我的回答满意吗?再答：再答：望采纳！再答：图片正在发送再答：发过去了再答：看不懂可以问我
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
符号好像有问题.x³+x²y-xy²-y³=x²(x+y)-y²(x+y)=(x+y)(x²-y²)=(x-y)(x+y
=xy(x^2-y^2)=xy(x+y)(x-y)
（x+3y）²-x-3y=（x+3y）²-（x+3y）=（x+3y）（x+3y-1）祝你学习进步,有不明白的可以追问!谢谢!
(x-y/3)^2-(x+y/3)^2=X^2-2XY/3+Y^2/9-X^2-2XY/3-Y^2*9=-4XY/3
6x(x-y)^2+3(y-x)^3=6x(x-y)^2-3(x-y)^3=3(x-y)^2[2x-(x-y)]=3(x-y)^2(x+y)
(x+y)^2-3(x+y)=(x+y)(x+y-3)
这个不能分解的,题目错了
请等一下再答：-x^3y^3-125=-（x^3y^3+125）=-（xy+5)(x^2y^2-5xy+25)