因式分解(2m-3n)²-2m 3n过程
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(m-n)^3+(2m+3n)^3=(m-n+2m+3n)(m^2+n^2-2mn+4m^2+9n^2+12mn-2m^2-mn+3n^2)=(3m+2n)(3m^2+9mn+13n^2)
平方差原式=[5m+(2n-3m)][5m-(2n-3m)]=(2m+2n)(8m-2n)=4(m+n)(4m-n)再问:因式分解(x+y)^2(x-y)-(x+y)(y-x)^2再答:做了这个也采纳
(2m-3n)^2-(2m-3n)=(2m-3n)(2m-3n-1)
(3m+2n)-(3m-2n)=3m+2n-3m+2n=4n2008+2008^2-2009^2=2008+(2008+2009)(2008-2009)=2008-(2008+2009)=-2009
9m^2-n^2+3m-n=(3m+n)(3m-n)+(3m-n)=(3m-n)(3m+n+1)
(m-n)²-1=(m-n)²-1²=(m-n-1)(m-n+1)很高兴为您解答,【学习宝典】团队为您答题.如追加其它问题,如果有其他需要帮助的题目,您可以求助我.
4m^2-(m+n)^2=(2m+m+n)(2m-m-n)=(3m+n)(m-n)
(3m+2n)-(3m-2n)=3m+2n-3m+2n=4n
(3m+n)(2m-n)-(m+3n)(n-2m)=(3m+n)(2m-n)+(m+3n)(2m-n)=(2m-n)(3m+n+m+3n)=4(m+n)(2m-n)
m(m-2n)+n(2mn-m^2)=m(m-2n)+n[m(2n-m)]=m(m-2n)(n+1)
(3m+2n)²-4(m-n)²=(3m+2n)²-2²(m-n)²=(3m+2n)²-(2m-2n)²=(3m+2n+2m-2n
(2m+3n)(2m-n)-4n(2m-n)=(2m-n)(2m+3n-4n)=2(2m-n)(m-2n)
2m^2012·(m-n)²-3m^2011·n(n²-m²)=2m^2012(m-n)²+3m^2011·n(m²-n²)=2m^2012
4m^2(m-n)+4n(n-m)=4m^2(m-n)-4n(m-n)=4(m-n)(m^2-n)
解原式=-(m-n)³(m-n)²-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5
5(M-N)^2+2(N-M)^3=5(M-N)^2-2(M-N)^3=(M-N)(5-2M+2N)再问:N和M换位不用变号吗再答:不是变负号了吗再问:第一步怎么算下去再答:5(M-N)^2+2(N-
原式=(m-n)²+2(m-n)-6=(m+n-2)(m+n+3)
2(3m+n)²-8=2[(3m+n)²-4]=2[(3m+n)²-2²]=2(3m+n+2)(3m+n-2)
(m-n)(m-1)再问:能写全过程吗?再答:这个是因式分解的十字分解法,是最基础的分解法的一种。
(3m+2n)²-4(m-n)²=(3m+2n)²-2²(m-n)²=(3m+2n)²-(2m-2n)²=(3m+2n+2m-2n