化简求值:[2 3x-2 x+y(x]

(x-2)²+∣y-3∣=0(x-2)²=0,∣y-3∣=0x=2y=3(x-y)/(x²-2xy+y²)-(xy+y²)/(x²-y

原式=[(x-y)/xy][4y^2/2(x-y)(x+y)-(x-y)^2/2(x-y)(x+y)+(x+y)^2/2(x-y)(x+y)]=[(x-y)/xy]{[4y^2-(x-y)^2+(x+

因式分解(x^2+1）×（3x-2）+（2x-3）（1+x^2)=(x²+1)(3x-2)+(2x-3)(x²+1)=(x²+1)(3x-2+2x-3)=5(x²

[2x的平方-(x+y)(x-y)][(-x-y)(y-x)+2y的平方]=[2x²-(x²-y²)][(x+y)(x-y)+2y²]=(2x²-x&

x(x+2y)-(x+1)+2x=x+2xy-x-2x-1+2x=2xy-1因为x=1/25,y=-25原式=2*1/25*（-25）-1=-3

（2X+3Y）²-（2X+Y）（2X-Y）=4X²+12XY+9Y²-（4X²-Y²）=4X²+12XY+9Y²-4X²

不用化了因为x=8,y=-8所以x+y=0式子中有个x+y所以整个式子的结果是0如果不懂,请追问,祝学习愉快!再问：步骤再答：x+y=0所以(x+y)(x-2y)(x²-4y²)=

原式可化为[(15x²+16xy+4y²)+(x²-4y²)]/4x=(16x²+16xy)/4x=4x+4y代入得4×2+4×3=20

:2(x-2y)^2-4(x-2y)+(x-2y)^2-3(x-2y)=2(x-2y)^2+（x-2y)^2-4(x-2y)-3(x-2y)=3（x-2y)^2-7(x-2y)=（x-2y）（3（x-

[23x-2x+y（x+y3x-x-y）]÷x−yx=（23x-23x+2）×xx−y=2xx−y，∵5x+3y=0，∴y=-53x，∴原式=2xx+53x=34．

[(x-y^2)+(x+y)(x-y)]÷2x=[x-y²+x²-y²]÷2x=[x²+x-2y²]/2x=(x+1)/2-y²/x,将x=

原式=[x^2-y^2-x^2+2xy-y^2+2xy-2y^2]/4y=2x-2y=2(x-y)=2*-3/2=-3很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

(x+2y)²-(x+y)(x-y)=x²+4xy+4y²-x²+y²=4xy+5y²=4x(-2)x(1/2)+5x(1/2)²

1、x/9(x-y)^2*(x-y)+(x^2+2-x-y)/(x+y)=x/9(x-y)+(x^2+2)/(x+y)-2=[(x(x+y)+9(x-y)(x^2+2)]/9(X-Y)(X+Y)-2=

【2x²-(x+y)(x-y)][(x+y-1)(x-y+1)+1-2y],=(2x²-x²+y²)[x²-(y-1)²+1-2y]=(x&

(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y

x/2-2(x-y^2)-(3x/2+y^2)=x/2-3x/2-2x+2y^2-y^2=-x-2x+y^2=-3x+y^2∵x=1/3,y=2原式=-1+4=3

原式=[(5x²+8xy-4y²)-(9x²-4y²)]÷4x=(-4x²+8xy)÷4x=-x+2y当x=2,y=-1时原式=-2-2=-4

X(X+2Y)-(X+1)^2+2X=x²+2xy-x²-2x-1+2x=2xy-1把x=1/25,y=-25代入得：2xy-1=-3

原式=12x-2x+2y2-32x-32y2=-3x+y2，当x＝13，y=2时，原式=-3×13+4=3．