化简求值:(x-y 4xy分之x-y)(x y-4xy分之x y)

你先把所有的因式展开,这样的话可以消去一些复杂的,像平方项就没有了,然后再将X的值代入就可以了,答案是-124

是(x^2/(x-1)-x+1)/(4x^2/(1-x)-4x+1)吗原式=(x-x+1)(x+x-1)/(x-1)/((4x^2-4x+1+4x^2-x)/(1-x))=-(2x-1)/(4x^2-

（x平方-4x+4分之x平方-4）-（x+2分之x-2）=[(x+2)(x-2)]/[(x-2)^2]-(x-2)/(x+2)=(x+2)/(x-2)-(x-2)/(x+2)=[(x+2)^2-(x-

原式=(x²-1-15)/(x-1)×(x-1)/(x-4)=(x²-16)/(x-4)=x+4当x=√3-4时原式=√3

(x-4)(2x-5)-(3x-2)(x+6)=(2x²-13x+20)-(3x²+16x-12)=2x²-13x+20-3x²-16x+12=-x²

（x-（x-4)/(x-3））÷（x-4）/（x-3）=（x²-4x+4）/（x-3)×（x-3）/（x-4）=（x-2)²/（x-4）.所以当x=根5时,原式=（根5-2）

（x-1-x+1分之8）除以x+1分之x+3=(x²-1-8)/(x+1)×(x+1)/(x+3)=(x+3)(x-3)/(x+1)×(x+1)/(x+3)=x-3=3-√2-3=-√2

(x-x分之1)除x分之x+1=(x²-1)/x÷（x+1)/x=(x+1)(x-1)÷(x+1)=x-1=√2+1-1=√2本题有什么不明白可以追问,

原式=（4xy+x²-2xy）/(x-2y)÷(x+2y)²/x²（4x-y）=x(x+2y)/(x-2y)÷(x+2y)²/x²（4x-y）=x&#

1/x+1+1/x-1.(x+1)(x-1)-x2+2x/x+2.(x-1)/x上式约分得到x-1=?x=2012即值为2011再问：没看明白唉→_→再答：电脑打不出格式来，所以看起来很麻烦。X的平方

结果-34,太简单了.

=(x-2)×2x/(x+2)(x-2)+4/(x+2)=2x/(x+2)+4/(x+2)=(2x+4)/(x+2)=22、(x-1-1)/(x-1)×(x-1)²/(x+2)(x-2)=(

原式=（x-2+2x+4)/(x+2)(x-2）*x(x+2)/3x+2)=x/(x-2)当x-2+根号3时,原式=（2+根号3）/（2+根号3）-2=（2根号3+3）/3

{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x

（4x-x^2)/(x-2)÷[x+2-12/(x-2)]=-x(x-4)/(x-2)÷[(x^2-16)/(x-2)]=-x(x-4)/(x-2)*(x-2)/[(x+4)(x-4)]=-x/(x+

5x=-3yx=-3|5y直接带进去得答案,或者=2\3x-2|3x+2|x+y的和乘（x+y）除以x-y|x=2乘x\x-y=2（-3\5y）\（-3\5y-y）=3\4手机果然不行.

解x²(x²-x+1)-x(x³-x²+x+1)=x^4-x³+x²-x^4+x³-x²-x=(x^4-x^4)+(x&

=(x²-1)/(x²-2x)-(x-1)/(x²-2x)=(x²-1-x+1)/(x²-2x)=(x²-x)/(x²-2x)=x

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

(x+1分之1+x-1分之1)·(x平方-1)=x+1分之1·(x平方-1)+x-1分之1·(x平方-1)=x-1+x+1=2x