先化简后求值x-1分之3x-x+1-搜答案-智慧作业帮

题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问：(x方-x)(x-2)方再答：

原式=[3x(x+1)-x(x-1)/x^2-1]×(x^2-1/2x)上面化到最后=[2x(x+2)/x^2-1]×x^2-1/2x=x+2当x=3时,原式=-3+2=-1(在键盘上打这个好辛苦啊~

x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/

(x-1分之x平方-1-x分之2x)除以x-1分之x,其中x=根号3+1=[x²/(x-1)+2x/(x-1)]÷x/(x-1)=x(x+2)/(x-1)*(x-1)/x=x+2其中x=根号

只有我能看懂吧?!再答：再答：题是这样的吗？再答：再问：你终于回来了再问：在吗再答：在再问：等等我去写题再问：去吧

(x-4)(2x-5)-(3x-2)(x+6)=(2x²-13x+20)-(3x²+16x-12)=2x²-13x+20-3x²-16x+12=-x²

1、(x-3分之2x-x+3分之x)乘x分之x平方-9=［2X(X+3)-X(X-3)］/［(X-3)(X+3)］*(X+3)(X-3)/X=［2X^2+6X-X^2+3X］/X=X+9当X=1时,原

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

=x^2+5x-1=1/9-5/3-1=-23/9

（x-1分之3x-x+1分之x）*x分之x的平方-1=[3x(x+1)-x(x-1)]/x=3(x+1)-(x-1)=3x+3-x+1=2x+4=2√2-4+4=2√2再问：确定么再答：确定啊，楼下也

结果-34,太简单了.

[3x/(x-1)-x/(x+1)]×(x²-1)/x=x[3(x+1)-(x-1)]/(x²-1)×(x²-1)/x=2x+4当x=√2-2时,原式=2x+4=2√2

原式=x^2/(x-1)+1/(1-x)=(x^2-1)/(x-1)=(x+1)(x-1)/(x-1)=x+1x=-3/2原式=-3/2+1=-1/2如果有疑问请点【评论】或者【追问】再问：-a分之1

（x+3）/（x²-9）+3/（x-3）=（x+3）/（x-3)(x+3)+3/（x-3）=1/（x-3）+3/（x-3）=4/（x-3）代入x=-1/2原式=4/（-1/2-3）=4/（-

（x²-1分之x-3）÷（x²+2x+1分之x²-2x-3)-(x+1分之1）=(x-3)/(x+1)(x-1)×(x+1)²/(x-3)(x+1)-1/(x+

原式=2x²-(7x-4x+3-2x²)=2x²-(3x+3-2x²)=2x²-3x-3+2x²=4x²-3x-3=4×1/4+3