作业帮先化简分式6x-6 x²-2x 1
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/08 17:59:15
X=-6x=-6(X/(X-2))*((X-6)/(X-3))=1-
x²+2x／x²-6x+9÷x²-4／x²-3x=x(x+2)/(x-3)^2*x（x-3）/（x+2)(x-2)=x^2/[(x-3)(x-2)]
是X/（X-2）-（1-X^2）/（X^2-5X+6）=2X/（X-3）吗?首先因式分解（X^2-5X+6）=（X-2）（X-3）,显然X不等于2且X不等于3,所以等式两边同乘以（X-2）（X-3）得
6x/(x+1)+2/(x^2+2x+1)=33x/(x+1)+1/(x+1)^2=33x(x+1)+1=3(x+1)^23x^2+3x+1=3x^2+6x+36x-3x=1-33x=-2x=-2/3
当分母x-6≠0，即x≠6时，分式2x−6有意义；故答案是：x≠6．
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
1,(X×3X)/3X+1/3X=(3X^2+1)/3X2,X/2X+(6×2X）/2X=(X+12X)/2X=13/23,(X-1)/X^2-[(9×X^2)/X^2]=[X-1-(9X^2)]/X
(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/
(X/(X-2))*((X-6)/(X-3))=1->X(X-6)=(X-2)(X-3)->X^2-6X=X^2-5X+6->X=-6
7/(x^2+x)+3/(x^2-x)=6/(x^2-1)7/x(x+1)+3/x(x-1)=6/(x-1)(x+1)分子分母同乘以x(x-1)(x+1),得7（x-1）+3（x+1)=6x10x-4
(x-y)/(y-x)³=-1/(x-y)²(x²-9)/(6-2x)=(x+3)(x-3)/[-2(x-3)]=-(x+3)/2(x²-1)/(x-x
档分母=0时,无意义x^2-5x-6=0x=-1或6当分子=0,分母不等于0时,分时=0,首先要保证分式有意义x^2-3x-4x=-1或4取x=4（-1时,分式无意义）
=2(x^2+3x-10)/-(x^2-5x+6)=2(x-2)×(x+5)/-(x-2)×(x-3)=2(x+5)/-(x-3)=2(x+5)/(3-x)
原式=(x+1)(x-6)/(x+1)²=(x-6)/(x+1)
(2x+1)/(x^2+x)=5/(6x+6)6(2x+1)=5x12x+6=5x7x=-6x=-6/7
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你
X-1/X-2-(X-2)/(X-3)=(X-5)/(X-6)-(X-6)/(X-7)(X-1)(X-3)-(X-2)²/（X-2）（x-3）=（X-5)(X-7)-(X-6)²/
分式计算：[(x²+2x)／(x²-6x+9)]÷[(x²-4)／(x²-3x)]原式=[x(x+2)/(x-3)²]•[x(x-3)/(