(x-y分之1-x²-xy分之2)÷3x分之x-2,其中x=2 tan60°
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1/(x-y)=(x+y)/(x²-y²)(xy+y²)/(x²-y²)=(xy+y²)/(x²-y²)
原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²
答案是零,左边约分剩下x/y
1/x-1/y=2001则(x-xy-y)/(x-y)=2002/2001
=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)
绝对算不出来再答:如果是一道题发图咯再问:x平方减xy加y平方分之x平方加2xy加y平方他给你条件是y分之x等于2分之1xy再问:吧xy无视掉再答:马上再答:化成Y等于2X在带入再问:然后怎么样再答:
1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3
(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2
原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)
1、(xy分之x²-y²)×(x-y分之x)-(y分之x);=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²
原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/
原式=xy/(x-y)(x+y)÷(2y)/(x-y)(x+y)=x/2再问:再问:
[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x
由已知条件可得:x-y=-4xy,(也就是在等式两边乘xy后整理,即可),代入所求的式子里分母为-4xy+7xy,即3xy;分子为-4xy-2xy,即-6xy,化简得-2
中间是÷?再问:不是,写错了,是分解应试再问:(x²分之x²-xy)÷(y分之x-x分之y)再答:这是计算吧,怎么可能是因式分解再问:那你按计算做再答:原式=【x²分之x
现将括号里的通分x2-y2可约去最后的y分之2再问:能具体一点吗再答:原式=((x+y+x-y)/(x2-y2)÷(x的平方-y的平方分之xy)=2x/(x2-y2)×(x2-y2)/xy=y分之2只
解1题原式=[(x+y)/x]-[x/(x-y)]+[y²/(x²-xy)]=[(x+y)/x]-[x/(x-y)]+{y²/[x(x-y)]}={(x+y)(x-y)/
原式=5x根号(xy)/3根号(y/x)*1/3根号(x/y)=5/9*根号(xy*x/y*x/y)=5x/9y根号(xy)
是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)一:原式=(x+2y)/(x+y)×[xy/(x+2y)]÷[(x+y)/xy]=x²y&sup
分子上应写:(x-1)²或者x²-2x+1再问:怎么书面表达呢?能否详细一些,谢谢再答:希望你及时采纳!!!!!