(3-a)(1-x)分之(a-3)x

6分之1-2x+3分之x+1=1-4分之2x+1两边乘122-4x+4x+4=12-6x-36x=3x=1/2代入x+3分之6x-a=6分之a-3x1/2+(3-a)/3=(a-3/2)/61/2+1

(x^2-3x+1)/(x^2-4)=30/(x+2)(x^2-3x+1)/(x-2)=30x^2-3x+1=30x-60x^2-33x+61=0x=(33±√1333)/2

A/(x-3)+1/(x+4)=[A(x+4)+(x-3)]/(x-3)(x+4)=(Ax+4A+x-3)/(x-3)(x+4)=[(A+1)x+(4A-3)]/(x-3)(x+4)∵(2x+1)/(

一题同意liooil的说法二题把X=4代入方程,得3x4+M=4M12=3MM=4所以,M-2=2三题〖A-2〗+〖B+1〗=0说明〖A-2〗=0〖B+1〗=0所以,A-2=0A=2B+1=0B=-1

3-x=3x+2,x=1/4ax-a^2=2x+ba=2,b=4.a不等于2时,x=（b+a^2）/(a-2)

=1/(a-x)-1/(a+x)-2x/(a²+x²)-4x³/(a^4+x^4)-8x^7/(a^8+x^8)=[(a+x)-(a-x)]/(a²-x

由于A/(X+6)+B/(X-3)=(AX-3A+BX+6B)/(X+6)(X-3)=(2X+1)/(x+6)(x-3)所以,A+B=2,6B-3A=1,解得,A=11/9B=7/9

(2x-3)/(x^2-x)=(2x-3)/x(x-1)A/(x-1)+B/x=(Ax+Bx-B)/x(x-1)=[(A+B)x-B]/x(x-1)两式对比A+B=2B=3A=2-B=-1所以A+B=

x-1分之A+x分之B=x^2-x分之Ax+x^2-x分之B(x-1)=x^2-x分之(A+B)x-B因此A+B=2B=3所以A=-1,B=3A-B=-4

(1)1/(x-1)+1/(1+x)=2x/(x^2-1)(2)a/(a²-1)+(3a+1)/(a²-1)+(2a+3)/(1-a²)=(a+3a+1-2a-3)/(a

右边通分：A/(X+1)+B/X=［AX+B(X+1)］/X(X+1)=［(A+B)X+B］/(X^2+X)与左边比较得方程组：A+B=2B=3解得：A=-1,B=3.∴A-B=-1-3=-4.

右边=[a(x-1)-b(3x+2)]/(x-1)(3x+2)=[(a-3b)x+(-a-2b)]/(3x²-x-2)=(4x-9)/(3x²-x-2)所以(a-3b)x+(-a-

（a-2）/（a²-1）÷（a-1）-（2a-1/a+1）=（a-2）/（a²-1）÷[（a+1)（a-1）-（2a-1）]/a+1）=（a-2）/（a²-1）÷（a&#

3a平方-1分之1-a因为1分之1就是1.所以=3a²-a-1x-x平方分之1+2x平方=2x²+x-1/x²-1+2x-x平方分之-2x+1=2x-x平方分之-2x因为

1/a+a/x=1/b+b/x1/a-1/b=b/x-a/x(b-a)/x=(b-a)/ab若b=a≠0,等式恒成立x不等于0即可b≠a则1/x=1/abx=ab综上b=a≠0,x≠0b≠a,x=a

(x-a)/(x-1)-3/x=1两边乘x(x-1)得x(x-a)-3(x-1)=x(x-1)x²-ax-3x+3=x²-x(a+2)x=3（1）a+2=0即a=-2时0=3,不成

A/(x+1)+B/(x-1)=(2x+3)/(x²-1)[(x-1)A+(x+1)B]/(x²-1)=(2x+3)/(x²-1)[Ax-A+Bx+B]/(x²

x分之x+3=3分之13x+9=x2x=-9x=-9/2a-b分之1-a+b分之1+a的平方+b的平方分之2b=(a+b)/(a+b)(a-b)-(a-b)/(a+b)(a-b)+2b/(a²