(2m^2n^-2)^2*3m^-3n^3=

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计算[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2

[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2=125(m+n)的6次方(m-n)³÷9(m+n)的4次方(m-n)²=125/9(m+n)²(m-n)如

计算(m+n)^3-(n+m)(m-n)^2

(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2

(m+5n)^2-2(5n+m)(n-3m)+(3m-n)^2

(m+5n)^2-2(5n+m)(n-3m)+(3m-n)^2=(m+5n)^2-2(m+5n)(n-3m)+(n-3m)^2=[(m+5n)-(n-3m)]^2=(4m+4n)^2=16(m-n)^

(m-n)^2 +n(n- m)

(m-n)^2+n(n-m)原式=(n-m)^2+n(n-m)=(n-m)(n-m+n)=(n-m)(2n-m)因为完全平方所以(m-n)^2=(n-m)^2(a-b)(3r-t)+9(b-a)(2t

(2m+3n)(2m-3n)-(3m-2n)(3m+2n)

(2m+3n)(2m-3n)-(3m-2n)(3m+2n)=(4m²-9n²)-(9m²-4n²)=4m²-9n²-9m²+4n&

计算(m-n)^3+(n-m)m^2

(m-n)^3+(n-m)m^2=(m-n)^3-(m-n)m^2=(m-n)[(m-n)^2-m^2]=(m-n)(m-n+m)(m-n-m)=-n(m-n)(2m-n)=-n(2m^2-3mn+n

(n-m)^3×(m-n)^2-(m-n)^5

(n-m)^3×(m-n)^2-(m-n)^5=-(m-n)^3*(m-n)^2-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^

(3m-2n)²+(3m+2n)(3m-2n)-9(m+n)²=(3m-2n)²-9(m+n)²+(3m+2n)(3m-2n)=(3m-2n+3m+3n)(3m

[(m-n)^2*(m-n)^3]^2/(m-n)^4

设m-n为a(a^2*a^3)^2/a^4=a^6即(m-n)^6

(m-n)+2n(m-n)

﹙m-n﹚²+2n﹙m-n﹚=﹙m-n﹚﹙m-n+2n﹚=﹙m-n﹚﹙m+n﹚.

因式分解(n-m)^3(m-n)^2-(m-n)^5

解原式=-(m-n)³(m-n)²-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

(2m+3n)(3m-2n)-(3m-2n)(3m+2n)

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已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?

m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=[m(m-n)+n(m+n)-n^2]/(m^2-n^2)=m^2/(m^2-n^2)=1/(1-(n/m)^2)=1/(1-(3/2)^2

已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))

已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)

设m n为自然数,定义m*n=m+(m+1)+(m+2)+(m+3)+.(m+n)

4.5*5=4.5+(4.5+1)+(4.5+2)+(4.5+3)+(4.5+4)+4.5+5)=4.5x6+1+2+3+4+5=27+15=42m*8=37.8m*n=m+(m+1)+(m+2)+(

3m(m+n)-6(m^2-n^2)

原式=3m(m+n)-6(m+n)(m-n)=(m+n)×【3m-6(m-n)】=(m+n)×(6n-3m)=3(m+n)(2n-m) 

m-n+2n^2/(m+n)

m-n+2n^2/(m+n)=[(m-n)(m+n)+2n^2]/(m+n)=(m^2+n^2)/(m+n)

2n(m+n)^2+2m(m+n)^2+(m+n)^3 分解因式:

2n(m+n)^2+2m(m+n)^2+(m+n)^3=(m+n)[2n(m+n)+2m(m+n)+(m+n)^2]=(m+n)[2(m+n)^2+(m+n)^2]=3(m+n)^3

3m(m-n)-2n(m-n)的平方

3m(m-n)-2n(m-n)²=(m-n)(3m-2mn+2n²)