⑴(1/x+1)+(1/x^2-1)-(1/x-1)⑵(1/x+1)-﹙x+2/x^2-1﹚×﹙x^2-2x+1/x^2
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/15 14:30:51
⑴(1/x+1)+(1/x^2-1)-(1/x-1)⑵(1/x+1)-﹙x+2/x^2-1﹚×﹙x^2-2x+1/x^2+4x+4﹚
①原式
=(x-1/x²-1)+(1/x²-1)-(x+1/x²-1)
=(x-1+1-x-1)/(x²-1)
=-1/x²-1
②原式
=(1/x+1)-(x+2)/(x+1)(x-1) × (x-1)²/(x+2)²
=(1/x+1)-(x-1)/(x+1)(x+2)
=(x+2)/(x+1)(x+2) - (x-1)/(x+1)(x+2)
=(x+2-x+1)/(x²+3x+2)
=3/(x²+3x+2)
=(x-1/x²-1)+(1/x²-1)-(x+1/x²-1)
=(x-1+1-x-1)/(x²-1)
=-1/x²-1
②原式
=(1/x+1)-(x+2)/(x+1)(x-1) × (x-1)²/(x+2)²
=(1/x+1)-(x-1)/(x+1)(x+2)
=(x+2)/(x+1)(x+2) - (x-1)/(x+1)(x+2)
=(x+2-x+1)/(x²+3x+2)
=3/(x²+3x+2)
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
先化简,再求值:[(x-2/x²+2x)-(x-1/x²+4x+4)]÷﹙x-4/x+2﹚,其中x&
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1
计算 x(x+3)-(x-1)(x-2)
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
化简 x(x-1)+2x(x+1)-3x(2x-5)