已知:△ABC与△ADE是等腰三角形,即AB=AC,AD=AE,且∠BAC=∠DAE.求证:BD=CE
已知:△ABC与△ADE是等腰三角形,即AB=AC,AD=AE,且∠BAC=∠DAE.求证:BD=CE
如图,在△ABC和△ADE中,∠BAC=∠DAE=90°,AB=AC,AD=AE,CE与BD相交于点M,BD交AC于点N
已知:如图所示,AB=AC,BD=CE,AD=AE,求证∠BAC=∠DAE
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE
已知:如图,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图6-7,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图,△ABC和△ADE都是等腰三角形,点D在BC上,AB=AC,AD=AE,∠BAC=∠DAE=90(2)若BD
如图,△ABC和△ADE均为等腰三角形.∠BAC=∠DAE=90°,AB=AC.AD=AE.
如图,AB=AE,AC=AD,BD=CE,求证:△ABC ≌ ADE.
已知如图等腰三角形ABC与DEF AB=AC AD=AE 且∠CAB=∠EAD 求证CE=BD
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△ACE.
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=90°.①求证:C