已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/04/25 07:48:42

已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy的值

（x+2）²+|x+y-10|=0
x+2=0
x+y-10=0
x=-2
y=12
3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy
=3x²y－（5x²y－2xy+x²y－2x²）－xy
=3x²y－（6x²y－2xy－2x²）－xy
=3x²y－6x²y+2xy+2x²+xy
=-x²y+3xy+2x²
=-4*12+3*(-2)*12+2*4
=-48-72+8
=-102

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