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计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/15 14:19:43
计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3^4-1)(3^4+1)(3^8+1)(3^16+1)+1
=(3^8-1)(3^8+1)(3^16+1)+1
=(3^16-1)(3^16+1)+1
=3^32-1+1
=3^32