(3x^3y^2+6x^2y^3)/(x+2y)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/09 14:27:13

(3x^3y^2+6x^2y^3)/(x+2y)
(-9m^2+4n^2)/(3m+2n)
(4a^2-20ab+25b^2)/(5b-2a)
(1-16a^4)/(4a^2+1)/(2a+1)

(1)
(3x^3y^2+6x^2y^3)/(x+2y) (分子提出公因子 3x^2y^2)
=3x^2y^2(x+2y)/(x+2y)
=3x^2y^2
(2)
(-9m^2+4n^2)/(3m+2n) (分子用平方差公式)
=(2n+3m)(2n-3m)/(3m+2n)
=2n-3m
(3)
(4a^2-20ab+25b^2)/(5b-2a) (分子用完全平方公式)
=(2a-5b)^2/(5b-2a)
=(5b-2a)^2/(5b-2a)
=5b-2a
(4)
(1-16a^4)/(4a^2+1)/(2a+1) (对 1-16a^4 用平方差公式)
=(1+4a^2)(1-4a^2)/[(4a^2+1)(2a+1)]
=(1-4a^2)/(2a+1) (再对 1-4a^2 用平方差公式)
=(1+2a)(1-2a)/(2a+1)
=1-2a

因式分解3x^2(x-y)+6x(y-x) 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)( [(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y) 化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方【x-3y][x+y]-[x-2y][x +2y]-[x-y 有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【- 2(2x+3y)(3x+2y)-(6x-y)(2x-5y) 1.（（y+2x)(-2x+y)+4(x+2y)^2)/3y 2.（2(x-y)^3-8(x-y）^2(x+y)+6y( x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6