化简：(1)(x+1)^2-x(x^2+x-1)-(x^2+1)^0(2)(y-2)(y^2-6y-9)-y(y^2-2

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/16 05:16:47

化简：(1)(x+1)^2-x(x^2+x-1)-(x^2+1)^0(2)(y-2)(y^2-6y-9)-y(y^2-2y-15)

（1）解原式=(x²+2x+1)-（x³+x²-x）-1
=x²+2x+1-x³-x²+x-1
=-x³+3x
（2）解原式=y(y²-6y-9)-2(y²-6y-9)-y(y²-2y-15)
=y³-6y²-9y-2y²+12y+18-y³+2y²+15y
=-6y²+18y+18
=-6×1/4+18×1/2+18
=-3/2+9+18
=51/2

1、x(x-y)(x+y)-x(x+y)^2 (1)(x^2/x)-y-x-y [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)( (1)(x+y)^2-(x-y)^2 1、(x-2y)(x+y) 已知4x=9y求(1)x+y/y (2)y-x/2x {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y 设x>1,y>0,若x^y+x^-y=2根号2,则x^y-x^-y等于 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y