设f(x)=x(x-1)(x-2)...(x-100),f'(0)=
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设f(x)=x(x-1)(x-2)...(x-100),f'(0)=
我知道答案是100!,但是我想要详细的过程,
我知道答案是100!,但是我想要详细的过程,
f ' (x)={x[(x-1)(x-2).(x-100)]}'
=x'*[(x-1)(x-2).(x-100)]+x*[(x-1)(x-2).(x-100)]'
=[(x-1)(x-2).(x-100)]+x*[(x-1)(x-2).(x-100)]'
f '(0)=[(x-1)(x-2).(x-100)]+0*[(x-1)(x-2).(x-100)]'
=[(0-1)(0-2).(0-100)]=100!(总共100数相乘为正)
=x'*[(x-1)(x-2).(x-100)]+x*[(x-1)(x-2).(x-100)]'
=[(x-1)(x-2).(x-100)]+x*[(x-1)(x-2).(x-100)]'
f '(0)=[(x-1)(x-2).(x-100)]+0*[(x-1)(x-2).(x-100)]'
=[(0-1)(0-2).(0-100)]=100!(总共100数相乘为正)
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