························

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/26 11:51:15

射线OA,OB,OC且OA⊥OB,角BOC=4O°，求角AOC的度数。(画图)

解题思路：分两种情形进行求解
解题过程：
解：
∵OA⊥OB，∴∠AOB＝90°
∴∠AOC＝∠AOB+∠BOC＝90°+40°＝130°
或∠AOC＝∠AOB-∠BOC＝90°-40°＝50°
最终答案：略

· ···· ·········· ····· 急··························· 化学··············· 求··············· 4··············· 急·························· 急 ··············急············ ········· ·····墙·········