数学number base问题

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/23 12:03:40

数学number base问题
如果（2^51+1) * (2^50+1) 被转换成 number base 2 (2进制）,那么这个2进制数有几个0?

十进制下的数2^51+1=2^51+2^0,转换成2进制,就是10…01,其中一共50个"0",
(2^51+1)(2^50+1)=2^101+2^51+2^50+1=2^101+2^51+2^50+2^0,
也就是说这是一个102位数,一共98个"0",4个"1"分别位于第1位、第51位、第52位以及最高位102位..
因此这个2进制数有98个"0"..

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