{An}{Bn},若lim(3An+Bn)=8,lim(6An-Bn)=1
lim(3an+4bn)=8 lim(6an-bn)=1 求lim(3an+bn) 要设3an+4bn=m 6an-bn
已知lim(3An+4Bn)=8,lim(6An-Bn)=1,求lim(3An+Bn)的值
已知lim(3an+4bn)=8,lim(6an-bn)=1,则lim(3an+bn)的值是多少
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
高二的极限运算题 lim(2an+4bn)=8,lim(6an-bn)=1,求lim(3an+bn)的值 n趋向于无穷大
关于数列的极限问题若极限lim(5an+4bn)=7,极限lim(7an-2bn)=5,则极限lim(6an+bn)=?
等差数列an,bn的前n项和分别为Sn,若Sn/Tn=2n/(3n+1),求lim an/bn
若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b=
若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1
(an+bn)/[根号下(an²+bn²)]=[1+(bn/an)]/根号下[1+(bn/an)