作业帮(a+1)(a-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)=
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/09 20:52:15
(a+1)(a-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)=
(a+1)(a--1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=(a^2--1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=(a^4--1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=(a^8--1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=.
=(a^1024--1)(a^1024+1)
=(a^2048--1).
=(a^2--1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=(a^4--1)(a^4+1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=(a^8--1)(a^8+1)(a^16+1)(a^32+1).(a^1024+1)
=.
=(a^1024--1)(a^1024+1)
=(a^2048--1).
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a
(a 1)(a 2)(a 3)(a
a(a-1)(a-2)(a-3)(a-4)因式分解
a/a-1÷（a-a/2a-1)
已知a^2+a+1=0,求1+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8的值
已知1+a+a^2=0求1+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8的值
（高一集合）已知A={2,4,a*a*a-2a*a-a+7},B={1,a+3,a*a-2a+2,a*a*a+a*a+3
a+a^2+a^3+a^4+a^5+a^6...+a^n=a^n+1-a/a-1 (a-1)≠0
先化简后,再求值:(a-2/a*a+2a-a-1/a*a+4a+4)/a-4/a+2其中a=根号2-1
(2a^2+3a+2)/(a+1)-(a^2-a-5)/(a+2)-(3a^2-4a-5)/(a-2)+(2a^2-8a
当a=1时,a-2a+3a-4a+5a…+99a-100a=
(4a+1)( )=16a^2+8a+1