4x(x-y+1)+y(y-2)
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
化简求值:【(x+Y)(X-Y)-(X-Y)的平方+2Y(2-Y)】除4Y,其中X=1 Y=2
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(
(2X-Y)²-4(X-Y)*(X+Y)-(X-Y)*(X-1)
(x-2y)²+(2x-4y)(x+y)+(x+y)²
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
(X-3Y)(X+3Y)-(X+2Y)(X-4Y)-(2X-Y)2的平方
(1)x-y/x-2y÷x^2-y^2/x^2-4xy+4y^2
因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y
计算:1/(2x) - 1/(x+y)((x+y)/(2x) - x - y)
已知:3x=8y.求(1)x+y/y (2)2x+3y/x-2y
(x-y/x+2y)³