1/(x+5)+1/(x-8)=1/(x+6)+1/(x+7)怎么解?简单方法!
解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值
解方程:x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
解方程(x+1/x+2)-(x+2/x+3)=(x+5/x+6)-(x+6/x+7)
解方程:x+2/x+1-x+3/x+2=x+6/x+5-x+7/x+6
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
(X+2)/(X+1)-(X+4)/(X+3)=(X+6)/(X+5)-(X+8)/(X+7)
X+(1/3)*(X+(1/3)*(X-9))=(1/9)*(X-9)用最简单的方法解方程
3x-1+5x=7x+x-3x这个方程怎么解