sin(-19/3π)tan7π/4
tan7分之3派与tan5分之2派 比较大小
若sin(π3
已知 cos π/5 =(根号5 +1)/4 求 sin π/5,sin -π/5 ,sin 4π/5 ,sin 3π/
α属于(0,π/2)且2sin²α-sinαcosα-3cos²α=0求sin(α+π/4)/sin
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
已知sin(π+α)=根号3/2,求sin(3/4π-α)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
已知sin(a-3π)=2cos(a-4π),求(sin(π-a)+5cos((3π/2)-a))/(2sin(3π/2
已知方程sin(a-3π)=2cos(a-4π),求 [sin(π-a)+5cos(2π-a)]/[2sin(3π/2-
化简:sin(4分之π-3x)cos(3分之π-3x)-sin(4分之π+3x)sin(3分之π-3x)
sin(π/4-3x)cos(π/3-3x)- sin(π/4+3x)sin(π/3-3x)=
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)