log9^27=
log9^8×log4^27=____.
log2 根号2+log9 27+4^log4 13=?
计算:log27(32)×log64(27)+log9(2)×log4(√27)=
(log2 3+log4 27)*(log3 4+log9 8)=
log4^27×log(8)25×log9^5
log9的五次=A log9的七次=B log3的35次?
已知log9 5=a,log9 7=b,求log35 9的值
log9(45)-log9(5)
log3 5-log3 15+1/2log9 27 的值
log2^根号下2+log9^27+4^(log4^13)
计算:(1/4)^log4^1/3-lg25-lg4-log9^27
计算:(log4 3+log8 3)×log9 √2=?