2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)
已知sin(π/6+a)=(根号3)/3,求sin(2π/3+a)?
f(x)=2sin[wx-(π/6)]sin[wx+(π/3)]=sin[2wx-(π/3)],求w的值,答案说w=1,
1.已知cos(π/6-α)=1/3,求sin(2/3π-α) 2.求证tan^2α-sin^2α=tan^2α-sin
化简:1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα
已知sinα是方程5x²-7x-6=0的根,求[sin(-α+3π/2)sin(π-α)tan²(2
sin²α+√3sinαcosα-2cos²α=0,α∈(π/6,5π/12),求:(1)sin(2
已知α∈(0,π|2),2tanα+3sinβ=7,且tanα-6sinβ=1,求sinα的值
已知6sin^2α+sinαcosα-cos^2α=0,求sin(2α+π/3)的值
已知函数f(x)=2sin(ax-π/6)sin(ax+π/3)
求证 cos(A)+ 根号3sin(A)=2sin(π/6+A)
sin(π/4+α)sin(π/4-α)=1/6 求sin2α