[(2x+y)²-y(y-4x)]÷[-1/4x]
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x
化简:[(2x-y)平方+(2x+y)(2x-y)-4x(x-y+1)]÷2x
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y