若m^2+3m-1=0,则【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/15 02:05:04

m^2+3m-1=0,m^2=1-3m
【(m-3)/(3m^2-6)】除以【(m+2)-(5)/(m-2)】
=[(m-3)/(3(m^2-2))] / [(m+2)-5/(m-2)]
=[(m-3)/(3(1-3m-2))] / [(m^2-4-5)/(m-2)]
=-[(m-3)/(3(3m+1))] / (m+3)(m-3)/(m-2)]
=-[(m-3)/(3(3m+1))] * [(m-2)/((m+3)(m-3))]
=-(m-2)/[3(3m+1)(m+3)]
=-(m-2)/[3(3m^2+10m+3)]
=-(m-2)/[3(3-9m+10m+3)]
=-(m-2)/[3(m+6)]
再问： ..亲，实在抱歉，应该是若m^2+3m-1=0,则【(m-3)/(3m^2-6m)】除以【(m+2)-(5)/(m-2)】
再答：你这不是害人嘛 m^2+3m-1=0, m^2+3m=1, m(m+3)=1 【(m-3)/(3m^2-6m)】除以【(m+2)-(5)/(m-2)】 =[(m-3)/(3m(m-2))] / [(m+2)-5/(m-2)] =[(m-3)/(3m(m-2))] / [(m^2-4-5)/(m-2)] =[(m-3)/(3m(m-2))] / (m+3)(m-3)/(m-2)] =[(m-3)/(3m(m-2))] * [(m-2)/((m+3)(m-3))] =1/[3m(m+3)] =1/3

m-2m-3m+4m-5m-6m+7m.2004m=? (m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=? (m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)= (m+3m+5m+.+2008m)-(2m+4m+6m+.+2009m) (m+3m+5m+...+2009m)-(2m+4m+6m+...2008m) 计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m) (m+3m+5m+...+2013m)-(2m+4m+6m+...+2012m) (m+3m+5m+...+2014m)-(2m+4m+6m+...+2013m) (1m+3m+5m+...+2009m)-(2m+4m+6m+...=2008m) (m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=? 若m(1-m^2)+m^3-2m+2012>=0,则m= 计算：（m+3m+5m+…+2015m）-(2m+4m+6m+…+2014m)=