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1/1x3+1/3x5+1/5x7+...+1/2007x2009=?

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/25 05:02:28
1/1x3+1/3x5+1/5x7+...+1/2007x2009=?
1/1x3+1/3x5+1/5x7+...+1/2007x2009
=(1-1/3)÷2+(1/3-1/5)÷2+(1/5-1/7)÷2+……+(1/2007-1/2009)÷2
=[(1-1/3)+(1/3-1/5)+(1/5-1/7)+……+(1/2007-1/2009)]÷2
=(1-1/3+1/3-1/5+1/5-1/7+……+1/2007-1/2009)÷2
中间互相抵消
=(1-1/2009)÷2
=2008/2009÷2
=1004/2009