求证:3+tan(A+60°)tan(A-60°)+tanAtan(A+60°)+tanAtan(A-60°)=0.
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求证:3+tan(A+60°)tan(A-60°)+tanAtan(A+60°)+tanAtan(A-60°)=0.
∵tan(A+60°)tan(A-60°)+tanAtan(A+60°)+tanAtan(A-60°)+3
=[tan(A+60°)tan(A-60°)+1]+[tanAtan(A+60°)+1]+[tanAtan(A-60°)+1]
=
tan(A+60°)−tan(A−60°)
tan120°+
tan(A+60°)−tanA
tan60°+
tanA−tan(A−60°)
tan60°
=−
tan(A+60°)−tan(A−60°)
tan60°+
tan(A+60°)−tanA
tan60°+
tanA−tan(A−60°)
tan60°
=0
得证
=[tan(A+60°)tan(A-60°)+1]+[tanAtan(A+60°)+1]+[tanAtan(A-60°)+1]
=
tan(A+60°)−tan(A−60°)
tan120°+
tan(A+60°)−tanA
tan60°+
tanA−tan(A−60°)
tan60°
=−
tan(A+60°)−tan(A−60°)
tan60°+
tan(A+60°)−tanA
tan60°+
tanA−tan(A−60°)
tan60°
=0
得证
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