整数指幂的运算：（1）(x^2+2xy+y^2/x^2-y^2)^-2 (2) (x^2-4y^2/(x^2-2xy)+

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/08 14:56:26

整数指幂的运算：（1）(x^2+2xy+y^2/x^2-y^2)^-2 (2) (x^2-4y^2/(x^2-2xy)+x-2y)^-1

(1). 原式=[(x+y)^2/(x+y)(x-y)]^-2
=[(x+y)/(x-y)]^-2
=(x-y)^2/(x+y)^2
(2).原式={(x+2y)(x-2y)/[x(x-2y)+(x-2y)]}^-1
=[(x+2y)(x-2y)/(x+1)(x-2y)]^-1
=[(x+2y)/(x+1)]^-1
=(x+1)/(x+2y)

（xy-x^2)乘以(xy)/(x-y) （x^2+xy/x-y)/（xy/x-y)计算 (x+y-2xy)(x+y-2)+(1-xy)² 整数x,y满足x2-y2=2xy,求x-y/x+y的值 x-y/x²÷x²-2xy+y²/xy*（xy-x²） x根号x+x根号y/xy-y^2)-（x+根号xy+y/x根号x-y根号）y xy(xy+1)+(xy+3)-2(x+y+2分之一）-(x+y-1)的平方因式分解：x×x-xy-2y×y-x-y x^2y+4xy+4y 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy) (x^2-xy)y÷y-x/xy怎么做?