(7y-3z)-(8y-5z)=-y+2z
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
2x+3y-z=11 2x+y-5z=8 -2+7y+z=19
(7y-3z)-(8y-5z)
x/2=y/3=z/5 x+3y-z/x-3y+z
三元一次方程组2x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4
解三元一次方程:x+y-z=0,2x+y+z=7,x-3y+z=8
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z
已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
x/10 = y/8 =z/9 求x+2y+3z/y-5z
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X