x2+x-(1/x)+(1/x2)=5又3/4 要写解题思路!
函数y=(x2-4x+3)/(2x2-x-1)的值域需要思路
1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4)
十字相乘法解题1)2x2-5x-12; (2)3x2-5x-2; (3)6x2-13x+5; (4)7x2-19x-6;
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
x2-5x+1=0则x2+x2/1
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21
x2+4x-5=0的解题过程
(x2+5x+4)2+2(x2+5x+4)2+1=(x2+.
解方程2/x2+x+3/x2-x=4/x2-1
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
先化简,再求值:(1)2x2-5x x2 4x,其中x=-3 (2)(3x2-xy-2y2)-2(x2 xy-2y2),
1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,